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A volume of 90.0 ml of aqueous potassium hydroxide (KOH) was strated against a standad solution of sulfuric acid (H2SO). What was the molarity of the KOH solution it 122 mL of 1.50 M H;SO, was needed? The equation is 2KOH(aq) + H, So,(aq)-→K½SO, (aq) + 2H;O(1) Express your answer with the appropriate units. > View Available Hint(s) molarity = 0.407 M

A volume of 90.0 ml of aqueous potassium hydroxide (KOH) was strated against a standad solution of sulfuric acid (H2SO). What was the molarity of the KOH solution it 122 mL of 1.50 M H;SO, was needed? The equation is 2KOH(aq) + H, So,(aq)-→K½SO, (aq) + 2H;O(1) Express your answer with the appropriate units. > View Available Hint(s) molarity = 0.407 M

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter12: Solutions
Section: Chapter Questions
Problem 12.104QE: A 10.00-mL sample of a 24.00% solution of ammonium bromide (NH4Br) requires 23.41 mL of 1.200 molar...
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A volume of 90.0 mL of aqueous potassium hydroxide (KOH) was titrated against a standard solution of sulfuric acid (H2SO). What was the molarity of the KOH solution it 12.2 mL of 1.50 M H2SO, was needed? The equation is 2KOH(aq) + H,SO. (aq)-»K2SO, (uq) + 2H, O(1) Express your answer with the appropriate units. > View Available Hint(s) molarity = 0.407 M Submit Previous Answers Correct The solution in the buret (in this case, H2SO4) is called the itrant. The sample in the flask (in this case, KOH) is called the analyte. The stage in a titration when the exact volume of solution needed to complete the reaction has been added is called the stoichiometric point or equivalence point. To detect the equivalence point, a few drops of an acid-base indicator are added to the analyte before the titration. Part B Redox titrations are used to determine the amounts of oxidizing and reducing agents in solution. For example, a solution of hydrogen peroxide, H2O2. can be titrated against a solution of potassium permanganate, KMNO,. The following equation represents the reaction: 2KMNO, (aq) + H,O, (aq) + 3H,SO. (aq)→ 30, (g) + 2MnSO, (aq) + K,SO. (aq) + 4H,O(1) A certain amount of hydrogen peroxide was dissolved in 100. mL of water and then titrated with 1.68 M KMNO4. What mass of H,O2 was dissolved if the titration required 13.3 mL of the KMNO, solution? Express your answer with the appropriate units. > View Avallable Hint(s)
Transcribed Image Text:A volume of 90.0 mL of aqueous potassium hydroxide (KOH) was titrated against a standard solution of sulfuric acid (H2SO). What was the molarity of the KOH solution it 12.2 mL of 1.50 M H2SO, was needed? The equation is 2KOH(aq) + H,SO. (aq)-»K2SO, (uq) + 2H, O(1) Express your answer with the appropriate units. > View Available Hint(s) molarity = 0.407 M Submit Previous Answers Correct The solution in the buret (in this case, H2SO4) is called the itrant. The sample in the flask (in this case, KOH) is called the analyte. The stage in a titration when the exact volume of solution needed to complete the reaction has been added is called the stoichiometric point or equivalence point. To detect the equivalence point, a few drops of an acid-base indicator are added to the analyte before the titration. Part B Redox titrations are used to determine the amounts of oxidizing and reducing agents in solution. For example, a solution of hydrogen peroxide, H2O2. can be titrated against a solution of potassium permanganate, KMNO,. The following equation represents the reaction: 2KMNO, (aq) + H,O, (aq) + 3H,SO. (aq)→ 30, (g) + 2MnSO, (aq) + K,SO. (aq) + 4H,O(1) A certain amount of hydrogen peroxide was dissolved in 100. mL of water and then titrated with 1.68 M KMNO4. What mass of H,O2 was dissolved if the titration required 13.3 mL of the KMNO, solution? Express your answer with the appropriate units. > View Avallable Hint(s)
Review I Constants I Periodic Table As a food chemist for a major potato chip company, you are responsible for determining the salt content of new potato chip products for the packaging label. The potato chips are seasoned with table salt, NaCl. You weigh out a handful of the chips, boil them in water to extract the salt, and then filter the boiled chips to remove the soggy chip pieces. You then analyze the chip filtrate for CIT concentration using the Mohr method.First you prepare a solution of silver nitrate, AGNO,, and titrate it against 0.500 g of KCI using the Mohr method. You tind that it takes 63.0 mlL of AgNO, titrant to reach the equivalence point of the reaction. You then use the same silver nitrate solution to analyze the chip filtrate in a Mohr reaction, finding that the solution yields a rusty brown precipitate when 45.7 mL of titrant is added. Part A If the sample of chips used to make the filtrate weighed 92.0 g. how much NaCl is present in ofe serving (115 g) of chips? Express your answer to three significant figures and include the appropriate units. > View Available Hint(s) HA salt/serving = Value Units
Transcribed Image Text:Review I Constants I Periodic Table As a food chemist for a major potato chip company, you are responsible for determining the salt content of new potato chip products for the packaging label. The potato chips are seasoned with table salt, NaCl. You weigh out a handful of the chips, boil them in water to extract the salt, and then filter the boiled chips to remove the soggy chip pieces. You then analyze the chip filtrate for CIT concentration using the Mohr method.First you prepare a solution of silver nitrate, AGNO,, and titrate it against 0.500 g of KCI using the Mohr method. You tind that it takes 63.0 mlL of AgNO, titrant to reach the equivalence point of the reaction. You then use the same silver nitrate solution to analyze the chip filtrate in a Mohr reaction, finding that the solution yields a rusty brown precipitate when 45.7 mL of titrant is added. Part A If the sample of chips used to make the filtrate weighed 92.0 g. how much NaCl is present in ofe serving (115 g) of chips? Express your answer to three significant figures and include the appropriate units. > View Available Hint(s) HA salt/serving = Value Units
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