A volume of 500.0 mL of 0.180 M NAOH is added to 545 mL of 0.250 M weak acid (K = 1.64 × 10-5). What is the pH of the resulting buffer? НА(аq) + ОН (аq) H,O(1) + A¯(aq) pH =
A volume of 500.0 mL of 0.180 M NAOH is added to 545 mL of 0.250 M weak acid (K = 1.64 × 10-5). What is the pH of the resulting buffer? НА(аq) + ОН (аq) H,O(1) + A¯(aq) pH =
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Buffer pH Calculation**
A volume of 500.0 mL of 0.180 M NaOH is added to 545 mL of 0.250 M weak acid (\(K_a = 1.64 \times 10^{-5}\)). What is the pH of the resulting buffer?
\[ \text{HA(aq) + OH}^-\text{(aq)} \rightarrow \text{H}_2\text{O(l) + A}^-\text{(aq)} \]
**pH =** [Text box for input]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1d39eb1c-3154-4bee-b19a-a1be6277f6e8%2Fd76829ed-2971-4af4-9673-23cc59d6a596%2Flyqj2uq_processed.png&w=3840&q=75)
Transcribed Image Text:**Buffer pH Calculation**
A volume of 500.0 mL of 0.180 M NaOH is added to 545 mL of 0.250 M weak acid (\(K_a = 1.64 \times 10^{-5}\)). What is the pH of the resulting buffer?
\[ \text{HA(aq) + OH}^-\text{(aq)} \rightarrow \text{H}_2\text{O(l) + A}^-\text{(aq)} \]
**pH =** [Text box for input]
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