A 0.0415 L volume of 0.11 M hypochlorous acid (HCIO), a weak acid with K₂ = 4.0x108, is titrated with 0.11 M potass a hydroxide (KOH), a strong base. Determine the pH at the following points in the titration. (a) before any KOH has been added с (b) after 0.0058 L KOH has been added Indicate which point is the equivalence point. O a b Od (c) after 0.0415 L KOH has been added
A 0.0415 L volume of 0.11 M hypochlorous acid (HCIO), a weak acid with K₂ = 4.0x108, is titrated with 0.11 M potass a hydroxide (KOH), a strong base. Determine the pH at the following points in the titration. (a) before any KOH has been added с (b) after 0.0058 L KOH has been added Indicate which point is the equivalence point. O a b Od (c) after 0.0415 L KOH has been added
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter14: Equilibria In Acid-base Solutions
Section: Chapter Questions
Problem 52QAP: A solution is prepared by dissolving 0.350 g of benzoic acid, HC7H5O2, in water to make 100.0 mL of...
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![A 0.0415 L volume of 0.11 M hypochlorous acid (HCIO), a weak acid with K₂ = 4.0x108, is titrated with 0.11 M potassium
a
hydroxide (KOH), a strong base.
Determine the pH at the following points in the titration.
(a) before any KOH has been added
с
(b) after 0.0058 L KOH has been added
Indicate which point is the equivalence point.
O a
b
Od
(c) after 0.0415 L KOH has been added](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F96201a2a-e1a8-43e0-87cb-09c681e265c1%2F8b0c777f-3b92-42de-a6a3-89b253f7f4db%2Fj5e4h0j_processed.png&w=3840&q=75)
Transcribed Image Text:A 0.0415 L volume of 0.11 M hypochlorous acid (HCIO), a weak acid with K₂ = 4.0x108, is titrated with 0.11 M potassium
a
hydroxide (KOH), a strong base.
Determine the pH at the following points in the titration.
(a) before any KOH has been added
с
(b) after 0.0058 L KOH has been added
Indicate which point is the equivalence point.
O a
b
Od
(c) after 0.0415 L KOH has been added
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Step 1: Determine the pH of the solution at each point from the given data:
VIEWStep 2: a. Calculation for pH of the solution before add any KOH:
VIEWStep 3: b. Calculation for pH of the solution after add 0.0058 L of KOH:
VIEWStep 4: c) Calculation for pH of the solution after add 0.0415 L of KOH:
VIEWStep 5: The equivalence point is:
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