A volume of 500.0 mL. of 0.130 M NaOH is added to 605 mL of 0.200 M weak acid (K, = 3.87 x 10-5). What is the pH of theresulting buffer?pH =HA (aq) + OH (aq) →→→ H₂O(l) + A (aq)-

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Answered: A volume of 500.0 mL of 0.130 M NaOH is…

A volume of 500.0 mL of 0.130 M NaOH is added to 605 mL of 0.200 M weak acid (K₂ = 3.87 x 10-5). What is the pH of the resulting buffer? pH = L HA(aq) + OH (aq) - H₂O(1) + A (aq)

Chemistry

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Electrolysis is defined as the process of breaking down ionic compounds into their constituent elements by passing a direct electric current through the compound in a fluid state. The cathode reduces cations, while the anode oxidizes anions. An electrolyte, electrodes, and some form of external power source are the main components required for conducting electrolysis. A partition, such as an ion-exchange membrane or a salt bridge, may also be used, but this is optional. These are primarily used to prevent the products from diffusing near the opposing electrode.

Question

A volume of 500.0 mL. of 0.130 M NaOH is added to 605 mL of 0.200 M weak acid (K, = 3.87 x 10-5). What is the pH of the
resulting buffer?
pH =
HA (aq) + OH (aq) →→→ H₂O(l) + A (aq)
-

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