< Question 12 of 19 > A volume of 500.0 mL of 0.110 M NaOH is added to 525 mL of 0.200 M weak acid (K₁ = 5.64 x 10-5). What is the pH of the resulting buffer? HA(aq) + OH(aq) -> → H₂O(1) + A¯(aq) pH =
< Question 12 of 19 > A volume of 500.0 mL of 0.110 M NaOH is added to 525 mL of 0.200 M weak acid (K₁ = 5.64 x 10-5). What is the pH of the resulting buffer? HA(aq) + OH(aq) -> → H₂O(1) + A¯(aq) pH =
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
![**Buffer Solution pH Calculation**
**Problem Statement:**
A volume of 500.0 mL of 0.110 M NaOH is added to 525 mL of 0.200 M weak acid (\( K_a = 5.64 \times 10^{-5} \)). What is the pH of the resulting buffer?
**Reaction:**
\[ \text{HA (aq)} + \text{OH}^- \text{(aq)} \rightarrow \text{H}_2\text{O (l)} + \text{A}^- \text{(aq)} \]
**To Find:**
The pH of the resulting buffer.
**Detailed Solution:**
To determine the pH of the resulting buffer solution after the addition of NaOH to the weak acid, a step-by-step calculation is required using the Henderson-Hasselbalch equation:
\[ \text{pH} = \text{p}K_a + \log \left(\frac{\text{[A}^- \text{]}}{\text{[HA]}}\right) \]
**Step 1: Calculate the moles of \(\text{HA}\) and \(\text{OH}^-\)**
- Moles of \(\text{HA} = \text{concentration} \times \text{volume}\)
\[ \text{Moles of HA} = 0.200 \text{ M} \times 0.525 \text{ L} = 0.105 \text{ mol} \]
- Moles of \(\text{OH}^- = \text{concentration} \times \text{volume}\)
\[ \text{Moles of OH}^- = 0.110 \text{ M} \times 0.500 \text{ L} = 0.055 \text{ mol} \]
**Step 2: Determine the limiting reagent and calculate the remaining moles of \(\text{HA}\) and \(\text{A}^- \)**
- Since \(\text{OH}^-\) is the limiting reagent:
\[ \text{Remaining moles of HA} = 0.105 \text{ mol} - 0.055 \text{ mol} = 0.050 \text{ mol} \]
\[ \text{Moles](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe32cdaa3-49b3-4b1d-929d-b728cde894e8%2Fa81e6571-ddfc-4972-b449-d17fda382de2%2Frffi1d8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Buffer Solution pH Calculation**
**Problem Statement:**
A volume of 500.0 mL of 0.110 M NaOH is added to 525 mL of 0.200 M weak acid (\( K_a = 5.64 \times 10^{-5} \)). What is the pH of the resulting buffer?
**Reaction:**
\[ \text{HA (aq)} + \text{OH}^- \text{(aq)} \rightarrow \text{H}_2\text{O (l)} + \text{A}^- \text{(aq)} \]
**To Find:**
The pH of the resulting buffer.
**Detailed Solution:**
To determine the pH of the resulting buffer solution after the addition of NaOH to the weak acid, a step-by-step calculation is required using the Henderson-Hasselbalch equation:
\[ \text{pH} = \text{p}K_a + \log \left(\frac{\text{[A}^- \text{]}}{\text{[HA]}}\right) \]
**Step 1: Calculate the moles of \(\text{HA}\) and \(\text{OH}^-\)**
- Moles of \(\text{HA} = \text{concentration} \times \text{volume}\)
\[ \text{Moles of HA} = 0.200 \text{ M} \times 0.525 \text{ L} = 0.105 \text{ mol} \]
- Moles of \(\text{OH}^- = \text{concentration} \times \text{volume}\)
\[ \text{Moles of OH}^- = 0.110 \text{ M} \times 0.500 \text{ L} = 0.055 \text{ mol} \]
**Step 2: Determine the limiting reagent and calculate the remaining moles of \(\text{HA}\) and \(\text{A}^- \)**
- Since \(\text{OH}^-\) is the limiting reagent:
\[ \text{Remaining moles of HA} = 0.105 \text{ mol} - 0.055 \text{ mol} = 0.050 \text{ mol} \]
\[ \text{Moles
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 5 steps

Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you

Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning

Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education

Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning

Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning

Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education

Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning

Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education

Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning

Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY