**Buffer Solution pH Calculation****Problem Statement:**A volume of 500.0 mL of 0.110 M NaOH is added to 525 mL of 0.200 M weak acid (\( K_a = 5.64 \times 10^{-5} \)). What is the pH of the resulting buffer?**Reaction:**\[ \text{HA (aq)} + \text{OH}^- \text{(aq)} \rightarrow \text{H}_2\text{O (l)} + \text{A}^- \text{(aq)} \]**To Find:**The pH of the resulting buffer.**Detailed Solution:**To determine the pH of the resulting buffer solution after the addition of NaOH to the weak acid, a step-by-step calculation is required using the Henderson-Hasselbalch equation:\[ \text{pH} = \text{p}K_a + \log \left(\frac{\text{[A}^- \text{]}}{\text{[HA]}}\right) \]**Step 1: Calculate the moles of \(\text{HA}\) and \(\text{OH}^-\)**- Moles of \(\text{HA} = \text{concentration} \times \text{volume}\) \[ \text{Moles of HA} = 0.200 \text{ M} \times 0.525 \text{ L} = 0.105 \text{ mol} \]- Moles of \(\text{OH}^- = \text{concentration} \times \text{volume}\) \[ \text{Moles of OH}^- = 0.110 \text{ M} \times 0.500 \text{ L} = 0.055 \text{ mol} \]**Step 2: Determine the limiting reagent and calculate the remaining moles of \(\text{HA}\) and \(\text{A}^- \)**- Since \(\text{OH}^-\) is the limiting reagent: \[ \text{Remaining moles of HA} = 0.105 \text{ mol} - 0.055 \text{ mol} = 0.050 \text{ mol} \] \[ \text{Moles

The pH of a solution is used to determine the acidity or alkalinity of a solution. The pH is…

< Question 12 of 19 > A volume of 500.0 mL of 0.110 M NaOH is added to 525 mL of 0.200 M weak acid (K₁ = 5.64 x 10-5). What is the pH of the resulting buffer? HA(aq) + OH(aq) -> → H₂O(1) + A¯(aq) pH =

< Question 12 of 19 > A volume of 500.0 mL of 0.110 M NaOH is added to 525 mL of 0.200 M weak acid (K₁ = 5.64 x 10-5). What is the pH of the resulting buffer? HA(aq) + OH(aq) -> → H₂O(1) + A¯(aq) pH =

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter16: Reactions Between Acids And Bases

Section: Chapter Questions

Problem 16.7QE

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