A voltaic cell is composed of the following 2 half reactions:Mn²+ (aq) + 2e→> Mn(s) Ecell = -1.185 VCu+ (aq) + e Cu(s) Eell = 0.521 VDetermine the non-standard state Ecell at 298 K when Mn²+ (aq) = 0.158 M and Cu+ (aq) = 0.663 M.→V Score on last try: 0 of 2 pts. See Details for more.You can retry this question belowDetermine the equilibrium constant, K, for the voltaic cell composed of the following 2 half reactions at298 K.2+Sn²+ (aq) ++2e → Sn(s) Ecell = -0.136 VMn2+²+ (aq) + 2e¯¯→ Mn(s) Ell-1.19 VReport your answer in the format 2.4E-3.1.87E-36Hint: Decide which half-reaction is the reduction reaction and which one is the oxidation reaction bylooking at Eº; the oxidation reaction should be reversed, and will have the opposite sign.4.0560949048976E+35

We have find out the non standard state at Ecell at 298K.

A voltaic cell is composed of the following 2 half reactions: Mn²+ (aq) + 2e → › Mn(s) Ecell = -1.185 V Cu+ (aq) + e Cu(s) Eell = 0.521 V Determine the non-standard state Ecell at 298 K when Mn²+ (aq) = 0.158 M and Cu+ (aq) = 0.663 M. → V

A voltaic cell is composed of the following 2 half reactions: Mn²+ (aq) + 2e → › Mn(s) Ecell = -1.185 V Cu+ (aq) + e Cu(s) Eell = 0.521 V Determine the non-standard state Ecell at 298 K when Mn²+ (aq) = 0.158 M and Cu+ (aq) = 0.663 M. → V

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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