A voltaic cell consists of a Zn/Zn half-cell and a Ni/Ni* half-cell at 25 °C. The initial concentrations What is the concentrations of Ni²+ when the cell potential falls to 0.45 V ? of Ni2+ respectively. The volume of half-cells is the same. and Zn2+ are 1.30 M and 0.130 M, Express your answer using one significant figure. (N*] = M Submit Previous Answers Request Answer X Incorrect; Try Again; 9 attempts remaining Part D What is the concentration of Zn*+ when the cell potential falls to 0.45 V ? Express your answer using two significant figures. ? [Zn?+] = M Submit Previous Answers Request Answer P Pearson Copyright © 2021 Pearson Education Inc. All rights reserved. Terms of Use | Privacy Policy | Permissions | Contact Us

A voltaic cell consists of a Zn/Zn half-cell and a Ni/Ni* half-cell at 25 °C. The initial concentrations What is the concentrations of Ni²+ when the cell potential falls to 0.45 V ? of Ni2+ respectively. The volume of half-cells is the same. and Zn2+ are 1.30 M and 0.130 M, Express your answer using one significant figure. (N] = M Submit Previous Answers Request Answer X Incorrect; Try Again; 9 attempts remaining Part D What is the concentration of Zn+ when the cell potential falls to 0.45 V ? Express your answer using two significant figures. ? [Zn?+] = M Submit Previous Answers Request Answer P Pearson Copyright © 2021 Pearson Education Inc. All rights reserved. Terms of Use | Privacy Policy | Permissions | Contact Us

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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What is the emf of this cell under standard conditions? Express your answer using three significant figures. A voltaic cell utilizes the following reaction and operates at 298 K 3Ce* (ag) + Cr(s)→3Ce (ag) + Cr" (ag). E = 2.35 V Submit Previous Answers v Correct Part B What is the emf of this cell when (Ce"]=2.9 M. [Ce1= 0.10 M, and [Cr+1= 1.4x10-2 M? Express your answer using two significant figures. ? E = V Submit Request Answer Part C What is the emf of the cell when [Ce*t] = 1.4x10-2 M [Ce+] = 2.0 M, and [Cr*] = 1.9 M ? Express your answer using two significant figures. E = V Submit Request Answer
Enter your answer in the provided box. What is the emf of a cell consisting of a Pb2+ / Pb half-cell and a Pt / H / H₂ half-cell if [Pb²+] = 0.64 M, [H] = 0.018 M and PH₂ = 1.0 atm ? V
Predict the potential for the following voltaic cell at 25 C:Cu(s)|CuSO4(1.29 M)||AgNO3(0.7 M)|Ag(s)
Cell Potential For a given galvanic cell, the standard cell potential can be calculated by subtracting the standard half-cell potential of the reaction that occurs at the cathode from the standard half-cell potential of the reaction that occurs at the anode: Ecell Ered (cathode) - Ed (anode) ▼ Tarnish on copper is the compound CuO. A tarnished copper plate i placed in an aluminum pan of boiling water. When enough salt is added so that the solution conducts electricity, the tarnish disappears. Imagine that the two halves of this redox reaction were separated and connected with a wire and a salt bridge. Part A Calculate the standard cell potential given the following standard reduction potentials: A²+ +3e Cu²+ + 20 Express your answer to two decimal places and include the appropriate units. ▸ View Available Hint(s) Ecell = li Value 4 → Units ? Al; E Cu; E 19 of 42 -1.66 V 0.340 V Review | Constants | Periodic Table
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Consider the cell described below. Al | Al³+ (1.00 M) || Pb²+ (1.00 M) | Pb Calculate the cell potential after the reaction has operated long enough for the [Al³+] to have changed by 0.45 mol/L. (Assume T= 25°C.) V Need Help? Read It Watch It
For the Zn-Cu2+ voltaic cell, we have Zn (s) + Cu2+ (aq, 1 M) → Zn2+(aq, 1 M) + Cu (s) Ecell 0 = 1.10 V Given that the standard reduction potential of Zn2+ to Zn(s) is -0.76 V, calculatethe ECu2+/Cu0 for the reduction of Cu2+ to Cu: Cu2+ (aq, 1 M) + 2e- → Cu (s)
half-cell and a are 0.0530 M MISSED THIS? Read Section 20.6 (Page). A voltaic cell consists of a Pb/Pb²+ Cu/Cu²+ half-cell at 25 °C. The initial concentrations of Pb²+ and Cu²+ 2+ and 1.70 M, respectively. What is the initial cell potential? Express your answer using two significant figures. ►View Available Hint(s) IVE ΑΣΦ Ecell: = Submit Part B 2+ What is the cell potential when the concentration of Cu Express your answer using two significant figures. ► View Available Hint(s) [5] ΑΣΦ Ecell = = Submit Part C ? V has fallen to 0.250 M? ? V What is the concentration of Pb²+ when the cell potential falls to 0.350 V ? Express your answers using three significant figures. ►View Available Hint(s)