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A voltaic cell consists of a Pb/Pb²+ half-cell and a Cu/Cu2+ half-cell at 25 °C. The initial concentrations of Pb2+ and Cu²+ are 0.0520 mol L¯1 and 1.60 mol L-1, respectively. Part A What is the initial cell potential? РЬ2+ (ад) + 2 е РЬ(s) Cu?+(aq) +2 e → Cu(s) E° = -0.13 V E° = 0.34 V Express your answer using two decimal places. µA Ecell = Value Units

A voltaic cell consists of a Pb/Pb²+ half-cell and a Cu/Cu2+ half-cell at 25 °C. The initial concentrations of Pb2+ and Cu²+ are 0.0520 mol L¯1 and 1.60 mol L-1, respectively. Part A What is the initial cell potential? РЬ2+ (ад) + 2 е РЬ(s) Cu?+(aq) +2 e → Cu(s) E° = -0.13 V E° = 0.34 V Express your answer using two decimal places. µA Ecell = Value Units

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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I need both parts please!!

A voltaic cell consists of a Pb/Pb²+ half-cell and a Cu/Cu²+ half-cell at 25 °C. The initial concentrations of Pb3+ and Cu²+ are 0.0520 mol L-1 and 1.60 mol L-1, respectively. Part B What is the cell potential when the concentration of Cu+ has fallen to 0.200 mol L-1? Pb2+(ag) + 2 e → Pb(s) Cu?+ (aq) + 2 e → Cu(s) E° = -0.13 V E° = 0.34 V Express your answer using two decimal places. HA Ecell = Value Units Submit Request Answer
Transcribed Image Text:A voltaic cell consists of a Pb/Pb²+ half-cell and a Cu/Cu²+ half-cell at 25 °C. The initial concentrations of Pb3+ and Cu²+ are 0.0520 mol L-1 and 1.60 mol L-1, respectively. Part B What is the cell potential when the concentration of Cu+ has fallen to 0.200 mol L-1? Pb2+(ag) + 2 e → Pb(s) Cu?+ (aq) + 2 e → Cu(s) E° = -0.13 V E° = 0.34 V Express your answer using two decimal places. HA Ecell = Value Units Submit Request Answer
A voltaic cell consists of a Pb/Pb²+ half-cell and a Cu/Cu?+ half-cell at 25 °C. The initial concentrations of Pb2+ and Cu²+ mol L-1 are 0.0520 mol L¯' and 1.60 Part A respectively. What is the initial cell potential? Pb2+ (aq) + 2 e¯ → Pb(s) Cu?+ (aq) + 2 e → Cu(s) E° = -0.13 V E° = 0.34 V Express your answer using two decimal places. μΑ Ecell = Value Units Submit Request Answer
Transcribed Image Text:A voltaic cell consists of a Pb/Pb²+ half-cell and a Cu/Cu?+ half-cell at 25 °C. The initial concentrations of Pb2+ and Cu²+ mol L-1 are 0.0520 mol L¯' and 1.60 Part A respectively. What is the initial cell potential? Pb2+ (aq) + 2 e¯ → Pb(s) Cu?+ (aq) + 2 e → Cu(s) E° = -0.13 V E° = 0.34 V Express your answer using two decimal places. μΑ Ecell = Value Units Submit Request Answer
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