A vertical summit curve has its highest point of the curve at a distance 48m from the P.T. The back tangent has a grade of +6% and a forward grade of -4%. The curve passes thru point “A” on the curve at station 25+140. The grade intersection is at station 25+160. Draw the diagram.   A.) Length of the parabolic curve B.) Stationing of the highest point C.) Difference in elevation between PVC and PVI D.) Difference in elevation between PVC and point A

Q: An equal-tangent vertical curve is to be constructed between grades of -3% and +2% (travelling left…

A: Given:- Downgrade of curve, g1 = -3% Upgrade of curve, g2 = +2% Station of PVI = 4 + 550.000…

Q: only need 23.2 PROBLEMS 23.1 A 1,500-ft vertical curve is to be used for joining a +3.0% grade line…

A: The given data is shown below: Length of curve=700 ftFirst grade=4.2%Second…

Q: The initail and final grades of a vertical curve having 2000 ft length are 2 % (plus) and 4 %…

A:

Q: A 1600-ft-long equal tangent sag vertical curve has the PVI at station 120+00 and elevation…

A: Given:- PVI station = 120+00 Elevation = 1500 ft Initial grade =-3.5% Final grade =+6.5% To find:-…

Q: 7. A -3% grade meets a +5% grade near an underpass. In order to maintain the minimum clearance…

A: jkjethgnfjhjjj

Q: 1. An equal-tangent crest vertical curve is being designed connects grades of 1.3% and -2.4% in the…

A:

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