A vertical crest curve has an approach grade +4% and a departure grade -3%.The Vertical Intersection Point level is 125m Australian Height Datum (AHD), withChainage 3405m.It is proposed to use a curve 550m long.Calculate:Chainage and Level at TP1Chainage and Level at TP2.Chainage and level at the apex point.

The curve in the surveying is of two type like horizontal and vertical curve. The vertical curve…

Answered: A vertical crest curve has an approach…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Q3/ A vertical curve below has a lower point (A) which exists at station (55+50) with elevation (1291.2 m). the back grade of (-8%) meet the forward grade of (+7.8%) at (PVI) station (54+00) with elevation (1281.5 m). determine the length of the curve with the stations of (PVC) and (PVT)? PVT PVC g₁=(-6%) PVI g₂=(+5.8%)
answer question 22 only
A -3% grade intersects a +2% grade at STA 4+350 meter at an elevation of 200.00 meter. Given that a 250 meter symmetrical parabolic curve is used, find, draw and plot the elevation of the curve at every 20 meter interval starting at STA 4+240 meter including its critical point
A vertical parabolic curve is to be used under a grade-separation structure. The curve is 250 m long and the minus grade of 3.8 percent intersects the plus grade of 5.4 percent at station of 0+120.424. Calculate the low point of the curve if the intersection at station 0+120.424 is at elevation 230.085 m.
solve using grade diagram
A +4.0% grade intersects a -3.0% percent grade at PVI Sta. 222+00 and Elevation 300.00 on a two-lane highway with a design speed of 45 mph. Assume AASHTO Standards. 1. Determine the minimum length for the curve that is designed to meet passing sight distance using K-value method 2. Determine the Station and Elevation of the PVC
3. A grade of-8% id followed by a grade of 3%, the grade intersecting at station 11+ 020 of elevation 423. 10 m. The change of grade is restricted to 0.5% in 25 meters. a. Compute the length of vertical parabolic curve b. Solve the lowest point of the curve from the P.T. c. Calculate the elevation at station 11+ 000.
Note : If you don't know the solution please leave it but don't give me wrong solution. A vertical curve joining entering grade of -4% with an exiting grade of - 7% begins at station 2+607 and is being designed with K value of 72. What is the station of the highest point on the curve . Code the station as the total distance from the origin, i.e., if the station is 1+100 code it as 1100.
Consider the same vertical curve from Problem 1 that has a +3.2% initial grade and -1.1% final grade. The point of vertical intersection is at station 98+20. The highest point of the curve is at station 100+79.35 to meet drainage design. What is the station of the point of vertical curvature (Also known as beginning of vertical curve). 92+88.95 92+90.81 92+88.05 (INCORRECT) 92+91.23 This is Question 1: Consider a vertical curve with a +3/2% initial grade and -1.1% final grade. The point of vertical intersection is at station 98+20. The highest point of the curve is at station 100+79.35 to meet drainage design. What is the design speed, in mph? Correct answer here is 70 MPH
ASAP PLS
The reduced level at the intersection of a rising gradient of 1.7% and a falling gradient of 2.3% on a proposed road is 52.50m. Given that K value is 55. The throught chainage of the intersection point is 4020m and proposed vertical curve is to have equal tangent. As a civil engineering you are required to prepare the following vertical curve design calculations : A) The through chainage of the points of the vertical curve if the minimum required length is to be used (LV) and the vertical curve setting out data at 20 metres interval. b) The chainage and reduced level of the highest point on the curve. c) Through chainage at highest point was located exactly under a bridge, if the RL of soffit is 57.42m, calculate the headroom based on proposed vertical curve design.
Choices: a) 8.8 m b) 7.9 m c) 7.7 m d) 7.8 m

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