**Sample Size, Mean, and Standard Deviation Analysis**To analyze the given data, we summarize it in the following table, rounding values to four decimal places as needed.| Variable | Sample Size | Mean | Standard Deviation ||-------------|--------------|---------|---------------------|| | 860 | 8.8410 | 2.1718 |**Verification of Assumptions for One-Sample t-Confidence Interval**Before creating a confidence interval, the following assumptions must be met:1. The observations in the sample must be randomly selected from the population or the sample should be selected in such a way that it is representative of the population. Based on what is known about how this sample was collected, the first assumption **has been met**.2. The sample size generally should be 30 or larger. Based on the sample size, the second assumption **has been met**.**Computation of Confidence Interval using SALT**To estimate the true population mean at the desired confidence level, enter the required values as detailed below and round them to three decimal places if needed.| Standard Error | 0.074059 ||--------------------|----------|| Degrees of Freedom | 859 || Lower Limit | || Upper Limit | |**Interpretation of Confidence Interval**To interpret the confidence interval, let's assume we have 90% confidence:- You can be **90%** confident that the true population mean **Coho salmon weight, in pounds, anglers might expect** is within the computed interval.- The method used to construct this interval estimate for the population mean is successful in capturing the actual population mean about **90%** of the time.

Given data Above the table Sample mean=8.841Standard deviation=2.1718Sample size=860Confidence…

Answered: (a) Use SALT to summarize the data and…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The population mean ACT composite score in 2015 was 20.8 points, with population standard deviation 5.6 points. The population size of number of tests taken in 2018 is extremely large (more than 1 million). Consider all samples of size 40 tests. find A and B
Use the sample information x⎯⎯x¯ = 37, σ = 6, n = 15 to calculate the following confidence intervals for μ assuming the sample is from a normal population.
Given two independent random samples with the following results: n₁ = 685 x₁ = 38 n₂ = 510 x2 = 287 Use this data to find the 99 % confidence interval for the true difference between the population proportions. Copy Data Step 1 of 4: Find the values of the two sample proportions, p₁ and 2. Round your answers to three decimal places.
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Suppose that the height of Asian males aged 35-44 in the United States is normally distributed with a standard deviation of 3 in. Jeremy takes a simple random sample of 16 such men and notices that none of them are unusually tall or unusually short. He then calculates the average of the sample to be 67 in. and is planning on using this to find a 90% z-confidence interval for the true mean height. Can Jeremy use this information to find the z-confidence interval? Complete the following sentences. The population distribution is and the population standard deviation is Therefore, the sample to find a 90% z-confidence interval.
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