A uniform rod of mass M and length L is held vertically by two strings of negligible mass, as shown below. The string on the right is cut and the bar falls, rotating about the left end. L/2 Mg Answer the following using the rotational form of Newton's second law for extended objects (1) 7 = la. (a) Immediately after the string is cut, what is the angular acceleration of the stick. (b) Is the angular acceleration constant during the fall? If not, is it decreasing or increasing as the bar falls?

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A uniform rod of mass M and length L is held vertically by two strings of negligible
mass, as shown below. The string on the right is cut and the bar falls, rotating about
the left end.
L/2
Mg
Answer the following using the rotational form of Newton's second law for extended
objects
(1)
7 = la.
(a) Immediately after the string is cut, what is the angular acceleration of the stick.
(b) Is the angular acceleration constant during the fall? If not, is it decreasing or
increasing as the bar falls?
The moment of inertia of a rod of length L and mass M rotating about an axis at the
end is given by I = {ML².
Note: The net gravitation force (and external force) acting on an extended object, is
equivalent to the force acting on a point mass M located at the center of mass. As a
result, the torque on the bar is determined by the force of gravity acting at the center
of mass.
Transcribed Image Text:A uniform rod of mass M and length L is held vertically by two strings of negligible mass, as shown below. The string on the right is cut and the bar falls, rotating about the left end. L/2 Mg Answer the following using the rotational form of Newton's second law for extended objects (1) 7 = la. (a) Immediately after the string is cut, what is the angular acceleration of the stick. (b) Is the angular acceleration constant during the fall? If not, is it decreasing or increasing as the bar falls? The moment of inertia of a rod of length L and mass M rotating about an axis at the end is given by I = {ML². Note: The net gravitation force (and external force) acting on an extended object, is equivalent to the force acting on a point mass M located at the center of mass. As a result, the torque on the bar is determined by the force of gravity acting at the center of mass.
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