A uniform horizontal strut weighs 400.0 N. One end of the strut is attached to a hinged support at the wall, and the other end of the strut is attached to a sign that weighs 200.0 N. The strut is also supported by a cable attached between the end of the strut and the wall. Assuming that the entire weight of the sign is attached at the very end of the strut, find the tension in the cable and the force at the hinge of the strut.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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A uniform horizontal strut weighs 400.0 N. One end of the strut is attached to a hinged support at the wall, and the other end of the strut is attached to a sign that weighs 200.0 N. The strut is also supported by a cable attached between the end of the strut and the wall. Assuming that the entire weight of the sign is attached at the very end of the strut, find the tension in the cable and the force at the hinge of the strut.

Options:
- A: T = 800 N, F = 721 N
- B: T = 700 N, F = 821 N
- C: T = 600 N, F = 521 N
- D: T = 700 N, F = 521 N

**Explanation:**

This problem involves calculating the tension in the supporting cable and the force at the hinge of the strut, utilizing equilibrium conditions in mechanical systems.

- **Strut Weight:** 400.0 N
- **Sign Weight:** 200.0 N

The task is to use static equilibrium conditions, meaning the sum of forces and the sum of moments around any point should be zero, to find possible answers from the given options.

- **Symbol T** represents the tension in the cable.
- **Symbol F** represents the force at the hinge.

To solve, consider balancing moments around the hinge and balancing vertical and horizontal forces.
Transcribed Image Text:A uniform horizontal strut weighs 400.0 N. One end of the strut is attached to a hinged support at the wall, and the other end of the strut is attached to a sign that weighs 200.0 N. The strut is also supported by a cable attached between the end of the strut and the wall. Assuming that the entire weight of the sign is attached at the very end of the strut, find the tension in the cable and the force at the hinge of the strut. Options: - A: T = 800 N, F = 721 N - B: T = 700 N, F = 821 N - C: T = 600 N, F = 521 N - D: T = 700 N, F = 521 N **Explanation:** This problem involves calculating the tension in the supporting cable and the force at the hinge of the strut, utilizing equilibrium conditions in mechanical systems. - **Strut Weight:** 400.0 N - **Sign Weight:** 200.0 N The task is to use static equilibrium conditions, meaning the sum of forces and the sum of moments around any point should be zero, to find possible answers from the given options. - **Symbol T** represents the tension in the cable. - **Symbol F** represents the force at the hinge. To solve, consider balancing moments around the hinge and balancing vertical and horizontal forces.
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