Answered: A rock is dropped from the top of a…

A rock is dropped from the top of a building. Rock starts from rest and it takes 7 seconds to reach the ground. How far did the rock travel in 7 seonds. Ignore air drag and friction. Use g =9.8m/s2.

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Question

A rock is dropped from the top of a building. Rock starts from rest and it takes 7 seconds to reach the ground. How far did the rock travel in 7 seonds. Ignore air drag and friction. Use g =9.8m/s². (Don't round your answer). Choose correct answer with the correct unit.

	A.	240.1 m/s
	B.	240.1 m
	C.	34.3 m/s
	D.	34.3 m

Expert Solution

Step 1

Given: The initial speed of the rock is zero.

The time taken by the rock to reach the ground is 7 seconds.

To determine: The distance the rock travel.

The kinematic equation to calculate the distance is

$s = u t + \frac{1}{2} a t^{2}$

where s is the distance, u is the initial speed, t is the time and a is the acceleration.

Here, the rock is dropped from the top of a building thus, the acceleration is acceleration due to gravity (g).

So, the equation becomes

$s = u t + \frac{1}{2} g t^{2}$ ................................. (1)

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