A uniform disk with radius R = 0.400 m and mass 30.0 kg rotates in a horizontal plane on a frictionless vertical axle that passes through the center of the disk. The angle through which the disk has turned varies with time according to θ(t) =(1.10 rad/s)t + (6.30 rad/s2)t2. What is the resultant linear acceleration of a point on the rim of the disk at the instant when the disk has turned through 0.100 rev?

icon
Related questions
Question

A uniform disk with radius R = 0.400 m and mass 30.0 kg
rotates in a horizontal plane on a frictionless vertical axle that passes
through the center of the disk. The angle through which the disk has turned
varies with time according to θ(t) =(1.10 rad/s)t + (6.30 rad/s2)t2.
What is the resultant linear acceleration of a point on the rim of the disk
at the instant when the disk has turned through 0.100 rev?

Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 9 steps with 19 images

Blurred answer
Similar questions
  • SEE MORE QUESTIONS