A two-way set associative cache memory uses blocks of four words. The cache can accommodate a total of 4096 words from main memory. The main memory size is 256K x 32. a) How many bits are there in tag, index, block, and word fields of the address format. b) How many bits are

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A: For a 4-way set associative cache, the length of the TAG field is given below:

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A: Here, I have to provide a solution to the above question.

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A:

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A: Block size = 32 words  Block Offset = 5 bits Total # of blocks inside cache = 16 So index bits = 4…

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A: Solution ;   Main memory = 256MB Main memory in bits = log2(256M) = log2(228) = 28 bits

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A: Answer to the above question is in step2.

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A: The answer for the tag and index fields respectively in the addresses generated by the processor is

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A:

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