A tube 1.30 m long is closed at one end. A stretched wire is placed near the open end. The wire is 0.235 m long and has a mass of 9.50 g. It is fixed at both ends and oscillates in its fundamental mode, By resonance, it sets the air column in the tube into oscillation at that column's fundamental frequency. (Use 343 m/s for the speed of sound in air.) (a) Find that frequency. 65.96 v Hz (b) Find the tension in the wire. 38 You need the formula for resonant frequencies in a tube with only one open end. The fundamental frequency of the tube matches the fundamental frequency of the wire. You need to use the formula for the resonant frequencies of a string. Can you get the linear density from the given mass and length? N D GO Tutorial
Properties of sound
A sound wave is a mechanical wave (or mechanical vibration) that transit through media such as gas (air), liquid (water), and solid (wood).
Quality Of Sound
A sound or a sound wave is defined as the energy produced due to the vibrations of particles in a medium. When any medium produces a disturbance or vibrations, it causes a movement in the air particles which produces sound waves. Molecules in the air vibrate about a certain average position and create compressions and rarefactions. This is called pitch which is defined as the frequency of sound. The frequency is defined as the number of oscillations in pressure per second.
Categories of Sound Wave
People perceive sound in different ways, like a medico student takes sound as vibration produced by objects reaching the human eardrum. A physicist perceives sound as vibration produced by an object, which produces disturbances in nearby air molecules that travel further. Both of them describe it as vibration generated by an object, the difference is one talks about how it is received and other deals with how it travels and propagates across various mediums.
Please help on following question!
T /u = (2fL)2
u = m/L = 9.5×10-3/ 0.235 = 40.4255× 10-3 kg/m
f = 65.96 Hz
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