A trapeze artist performs an aerial maneuver. While in a tucked position, as shown in Figure A, she rotates about her center of mass at a rate of ωi=5.79 rad/s. Her moment of inertia about this axis is ?i=16.7 kg·m^2. A short time later, the aerialist is in the straight position, as shown in Figure B. If the moment of inertia about her center of mass in this position is now ?f=30.7 kg·m^2, what is her rotational speed ?f?

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A trapeze artist performs an aerial maneuver. While in a tucked position, as shown in Figure A, she rotates about her center of mass at a rate of ωi=5.79 rad/s. Her moment of inertia about this axis is ?i=16.7 kg·m^2. A short time later, the aerialist is in the straight position, as shown in Figure B. If the moment of inertia about her center of mass in this position is now ?f=30.7 kg·m^2, what is her rotational speed ?f?

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Given data, 

Initial moment of inertia Ii=16.7 kgm2Initial angular speed ωi=5.79 rad/sfinal moment of inertia If=30.7 kgm2final angular speed ωf=??According to conservation of angular momentum  Initial angular momentum = final angular momentum

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