A figure skater wants to spin faster. With her arms and leg outstretched, she has a moment of inertia1 = 3.6 kgm2 and a spin rate of 2.0 rev/s. If she can squeeze her arms and leg closer to her rotation axis, she can spin at a rate of 24 rev/s. What is her new moment of inertia for the faster spin? O 1.9 kgm2 O 0.30 kgm2 O 7.2 kgm2 O 45 kgm2

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### Understanding Moments of Inertia and Angular Velocity

#### Problem Statement:

A figure skater wants to spin faster. With her arms and legs outstretched, she has a moment of inertia \( I \) = 3.6 kgm\(^2\) and a spin rate of 2.0 rev/s. If she can squeeze her arms and legs closer to her rotation axis, she can spin at a rate of 24 rev/s. What is her new moment of inertia for the faster spin?

#### Options:

- 1.9 kgm\(^2\)
- 0.30 kgm\(^2\)
- 7.2 kgm\(^2\)
- 45 kgm\(^2\)

#### Explanation:

The relationship between the moment of inertia \( I \) and angular velocity \( \omega \) for a rotating body is governed by the conservation of angular momentum. Angular momentum \( L \) is given by:

\[ L = I \omega \]

Since angular momentum is conserved, the initial angular momentum \( L_1 \) must equal the final angular momentum \( L_2 \):

\[ L_1 = L_2 \]

Therefore:

\[ I_1 \omega_1 = I_2 \omega_2 \]

Given:
- \( I_1 = 3.6 \) kgm\(^2\)
- \( \omega_1 = 2.0 \) rev/s
- \( \omega_2 = 24 \) rev/s

We need to find \( I_2 \):

\[ I_2 = \frac{I_1 \omega_1}{\omega_2} \]

Substitute the values:

\[ I_2 = \frac{3.6 \, \text{kgm}^2 \times 2.0 \, \text{rev/s}}{24 \, \text{rev/s}} \]

\[ I_2 = \frac{7.2 \, \text{kgm}^2 \text{ rev/s}}{24 \, \text{rev/s}} \]

\[ I_2 = 0.30 \, \text{kgm}^2 \]

Hence, the correct answer is:

\[ \boxed{0.30 \, \text{kgm}^2} \]
Transcribed Image Text:### Understanding Moments of Inertia and Angular Velocity #### Problem Statement: A figure skater wants to spin faster. With her arms and legs outstretched, she has a moment of inertia \( I \) = 3.6 kgm\(^2\) and a spin rate of 2.0 rev/s. If she can squeeze her arms and legs closer to her rotation axis, she can spin at a rate of 24 rev/s. What is her new moment of inertia for the faster spin? #### Options: - 1.9 kgm\(^2\) - 0.30 kgm\(^2\) - 7.2 kgm\(^2\) - 45 kgm\(^2\) #### Explanation: The relationship between the moment of inertia \( I \) and angular velocity \( \omega \) for a rotating body is governed by the conservation of angular momentum. Angular momentum \( L \) is given by: \[ L = I \omega \] Since angular momentum is conserved, the initial angular momentum \( L_1 \) must equal the final angular momentum \( L_2 \): \[ L_1 = L_2 \] Therefore: \[ I_1 \omega_1 = I_2 \omega_2 \] Given: - \( I_1 = 3.6 \) kgm\(^2\) - \( \omega_1 = 2.0 \) rev/s - \( \omega_2 = 24 \) rev/s We need to find \( I_2 \): \[ I_2 = \frac{I_1 \omega_1}{\omega_2} \] Substitute the values: \[ I_2 = \frac{3.6 \, \text{kgm}^2 \times 2.0 \, \text{rev/s}}{24 \, \text{rev/s}} \] \[ I_2 = \frac{7.2 \, \text{kgm}^2 \text{ rev/s}}{24 \, \text{rev/s}} \] \[ I_2 = 0.30 \, \text{kgm}^2 \] Hence, the correct answer is: \[ \boxed{0.30 \, \text{kgm}^2} \]
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