A thin layer of oil (n = 1.25) is on top of a puddle of water (n = 1.33). If normally %3D incident 500-nm light is strongly reflected, what is the minimum nonzero thickness of the oil layer?
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- Monochromatic, in phase light of wavelength > 752nm is incident on a piece of metal with either one or two slits on it - it is difficult to see to determine which. The diffraction pattern is observed on a viewing screen that is located 55cm away from the metal plate. The first two minima are measured to be 2.3cm and 7.0cm away from the central maxima. What is the brightness of the light at a distance of 6.3cm from the central maxima, relative to the brightness of the central maxima? x10-3 Note: Brightness is proportional to the SQUARE of the amplitude. For double slit, this means I = I (cos(d sin ) º)) ². 2 I = I₂ sin (5) xd sin 0 . For single slit, this means In both of these, I, is the maximum brightness, and d is the characteristic spacing of the slit(s).A thin layer of oil (n=1.28) spills onto the surface of a nearby lake (water has n=1.33). It produces maximum reflection for orange ligh ( 580 nm wavelength). Assuming the maximum occurs in the first order, determine the thickness of the oil slick. Note that by "first order" we mean that this is the minimum amount of shifting required for reflection to occur.Problem 1: In a double slit experiment the first minimum for 415 nm violet light is at an angle of 42°. Randomized Variables 2 = 415 nm e = 42 ° Find the distance between the two slits in micrometers. d= 8 9 5 6 sin() cos() tan() 7 HOME cotan() asin() acos() E A 4 atan() acotan() sinh() 1 2 3 cosh() tanh() cotanh() END O Degrees O Radians Vol BACKSPACE DEL CLEAR +
- Problem 2: Consider light that has its third minimum at an angle of 23.6° when it falls on a single slit of width 3.55 μm. Randomized Variables 9 = 23.6° w = 3.55 um D Find the wavelength of the light in nanometers. λ=1 sin() cos() cotan() asin() atan() acotan() tanh() cosh() O Degrees Hints: 2% deduction per hint. Hints remaining: 2 Submit tan() JU acos() E sinh() cotanh() Radians Hint ( + 7 8 9 4 5 6 1 0 VO BACKSPACE Feedback 2 3 All content © 2022 Expert TA, LLC DEL HOME END I give up! Feedback: 2% deduction per feedback. CLEARA particular person's pupil is 4.5 mm in diameter, and the person's normal‑sighted eye is most sensitive at a wavelength of 552 nm. What is angular resolution ?R of the person's eye, in radians?If a 600nm light is incident on a 300 lines/mm diffraction grating, what is the distance of the third order bright fringe from the central max given that the grating is 20cm from the screen.
- A diffraction grating has a grating constant of 415 lines/mm. If composite light with wavelengths of 601 nm and 461 nm are incident upon the grating, what is there angular separation in the 1st order spectrum? Answer this with a positive number of degrees.A laser light with wavelength of, N = 630nm, allowed to pass through double slit interference with a separation distance of, d= 0.03mm. The distance between the slits and the board is x-1.5 meter: What is the distance in cm for the fourth bright maxima, ÿ4 from center of the screen?The full width at half-maximum (FWHM) of a central diffraction maximum is defined as the angle between the two points in the pattern where the intensity is one-half that at the center of the pattern. (See figure (b).) (a) Does the intensity drop to one-half the maximum value when sin²α = a²/2? (b) Is a = 1.39 rad (about 80°) a solution to the transcendental equation of (a)? (c) Is the FWHM AÐ = 2sin¹(0.442 A/a), where a is the slit width? Calculate the FWHM of the central maximum for slit width (d) 1.17 A, (e) 5.03 A, and (f) 11.7 A. 20 20 Relative intensity 15 10 0.8 0.6 a=2 0.4 0.2 5 05 8 (degrees) (a) 10 15 20 20 Relative intensity 1.0 0.8 0.6 -A0- 0.4 0.2 a= 52 20 15 10 5 0 5 10 15 20 (degrees) (b)
- The limit to the eye's acuity is actually related to diffraction by the pupil. What is the angle between two just-resolvable points of light for a 2.75 mm diameter pupil, assuming the average wavelength of 539 nm? angle between two points of light: Take the result to be the practical limit for the eye. What is the greatest possible distance a car can be from a person if he or she can resolve its two headlights, given they are 1.40 m apart? greatest distance at which headlights can be distinguished: m What is the distance between two just-resolvable points held at an arm's length (0.900 m) from a person's eye? distance between two points 0.900 m from a person's eye: ma) At what angle is the first minimum for 550-nm light falling on a single slit of width 1.00 um? When i solve the question, there is no way i get the answer to be 33.4 deg. rather i get the sin-1 (0.55) = 0.58. IS the final answer wrong in the bartley and the test book or am i wrong?