Monochromatic, in phase light of wavelength > 752nm is incident on a piece of metal with either one or two slits on it - it is difficult to see to determine which.The diffraction pattern is observed on a viewing screen that is located 55cm away from the metal plate. The first two minima are measured to be 2.3cm and 7.0cm awayfrom the central maxima.What is the brightness of the light at a distance of 6.3cm from the central maxima, relative to the brightness of the central maxima?x10-3Note: Brightness is proportional to the SQUARE of the amplitude. For double slit, this means I = I (cos(d sin )º)) ².2I = I₂sin(5)xd sin 0. For single slit, this meansIn both of these, I, is the maximum brightness, and d is the characteristic spacing of the slit(s).

Solution: Between the first two minima, there will be first maxima and for the first maxima,…

Answered: onochromatic, in phase light of…

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