Answered: A the moving rod has a resistance of…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

A the moving rod has a resistance of 0.25 Ω and moves on rails 20.0 cm apart. The stationary U-shaped conductor has negligible resistance. When a force of 0.410 N is applied to the rod, it moves to the right at a constant speed of 1.50 m/s. What is the magnetic field?

Expert Solution

Step 1: Determine the given data and expression:

Given:

The resistance of rod is R=0.25 Ω.
The distance moved is L=20 cm=0.20 m
The force applied on rod is F=0.410 N.
The speed is v=1.50 m/s.

The expression for magnetic force is:

$table row F equals cell B i L end cell row F equals cell B open parentheses fraction numerator B v L over denominator R end fraction close parentheses L end cell row F equals cell fraction numerator B squared v L squared over denominator R end fraction end cell row B equals cell square root of fraction numerator F R over denominator v L squared end fraction end root end cell end table$

Here, B is the magnetic field, and i is the current.

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