10-12 kg
Q: A proton moves with a velocity of = (61 - 5j + k) m/s in a region in which the magnetic field is B =…
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Q: A 30.0-g metal ball having net charge Q = 5.10 µC is thrown out of a window horizontally north at a…
A: Given Data: Mass of the object (m) = 30.0 g = 30.0×10-3 kg.Charge on the object (Q) = 5.10 μC =…
Q: In the figure below, the current in the long, straight wire is I1 = 5.1 A and the wire lies in the…
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Q: A long, straight wire lies along the y-axis and carries a current 8.00 A in the -y-direction (Figure…
A: Part (1 of 3) Basic Details The magnetic field depends on the length, the permeability of free…
Q: Derive an expression for the magnitude of the magnetic field (c) at points within the outer…
A: As the currents in both the conductors are oppositely directed, the magnetic fields being generated…
Q: Two hikers are reading a compass under an overhead transmission line that is 5.40 m above the ground…
A: Distance above the ground (r) = 5.40 m Current (I) = 785 A north to south Let r be the distance from…
Q: An alpha particle α is really a helium 4/2He nucleus. If all of its electrons are stripped off…
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Q: I Two long straight wires carrying 6 A of conventional current are connected by a…
A: Solution:The formula for magnetic field is given as:Barc = μ0I4πr×ϕ =μ0I4πr×3π2…
Q: The magnetic field in a region is given by B = (0.7501 + 0.230ĵ) T. At some instant, a particle with…
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Q: Two particles A and B of masses m and me respectively and having the same charge are moving in a…
A: Here, two particles A and B are travelling on a plane with masses mA and mB, respectively, with the…
Q: A charged particle with a mass of 2.58x10-22 kg and a charge of ±2.31x10-17 C enters a magnetic…
A: Note: As per the company policy only the first 3 subparts are solved below, to get answers for the…
Q: A particle with mass 3x10-2 kg and charge +4 μC enters a region of space where there is a magnetic…
A: The mass of the particle, The charge, The magnetic field, The aceleration is
Q: A toroid has 450 turns of wire and carries a current of 12 A. Its inner and outer radii are 6.6 and…
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Q: A proton moves with a velocity of V = (4î - 4j + k) m/s in a region in which the magnetic field is B…
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Q: • Part A A positive charge q moves to the right with speed v and enters a region with a uniform…
A: Here uniform magnetic field and electric field are perpendicular to each other. If a charged…
Q: A capacitor C= 25.0 µF is connected to two long parallel conducting rails L = 0.333 m apart. A…
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Q: A uniform magnetic field points vertically upward; its magnitude is 0.480 T. An electron with…
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Q: A charged particle is accelerated through a potential of 200.0 volts from rest and achieves a speed…
A: Using Work energy theorem The change in the kinetic energy of the particle is equal to net work done…
Q: A metal rod (mass m = 0.10 kg, resistance R = 2.0 2) is lying on top of two conducting rails that…
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Q: 8. In a mass spectrometer a charged particle is accelerated to a velocity v = 5.9 107 m/s by an…
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Q: A proton moves with a velocity of V = (51-5j + k) m/s in a region in which the magnetic field is B =…
A: The velocity of the proton is v=5i-5j+k m/s. The magnetic field is B=i+2j-k T.
Q: The earth's magnetic field, with a magnetic dipole moment of 8.0 x 1022 A m², is generated by…
A: Given data: The magnetic dipole moment of the earth is μe=8.0×1022 Am2 The diameter of the current,…
Q: n (Figure 1), the moving rod has a resistance of 0.25 ? and moves on rails 20.0?cm apart. The…
A: Given: Resistance of rod is 0.25 ohm Distance of rails is 20 cm Force is 0.470 N Speed is 1.6 m/s
Q: A charged particle (m = 6.0 ✕ 10-9 kg; q = 5.0 ✕ 10-6 C) moves in uniform magnetic field given by =…
A: Mass of the particle, m= 6×10-9kgCharge of the particle, q=5×10-6CMagnetic field,…
Q: A positively charged particle, q, of mass m moves at a constant velocity along the x direction. The…
A: Drag Force: This force is exerted by the fluid on the object traveling through it and it opposes its…
Q: n nucleus which has a net positive charge) is moving due at is directed due north. Which one of the…
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Q: A horizontal copper wire of mass 4.0 x 10-3 kg and length 80 mm is placed perpendicular to a…
A: Given: mass m = 4.0*10-3 kg length L = 80mm = 0.08 m magnetic flux density B = 0.16 T To find:…
Q: 21. An electron (q = -1.60 × 1019 C, me = 9.11 × 10–31 kg) with an instantaneous velocity v = 1.50 x…
A: (d) The direction of force is given by the Fleming's left hand rule so that it moves in clockwise…
n the figure, a small particle of charge -1.7 × 10-6 C and mass m = 2.1 × 10-12 kg has speed v0 = 7.1 × 103 m/s as it enters a region of uniform magnetic field. The particle is initially traveling perpendicular to the magnetic field and is observed to travel in the semicircular path shown with radius R = 3.0 cm. Find the magnitude and direction of the magnetic field in the region. Make sure to explain how you've determined the direction of the magnetic field
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- Several electrons move at speed 6.40 × 105 m/s in a uniform magnetic field with magnitude B = 0.600 T directed downward. Find the magnetic force on the electron at point a. N out of the pageUniform magnetic field B is shown in the image as blue-color arrows in the horizontal direction. A wire of lengths L carrying current, i, is place on the page perpendicular to the magnetic field flowing up. What is the direction and magnitude of the magnetic force on the current-carrying wire?how do you do part d? this is a non graded practice worksheet
- B Consider a straight current-carrying wire of length / oriented perpendicular to a magnetic field of strength B. If the current through wire is I then the force on this wire segment is 1.5 N. Calculate the magnitude of the magnetic force on this wire if it is reshaped into a semi-circle. The current through the wire, it's length and orientation relative to the magnetic field remain the same. t X X X x X x x x The force on the semi-circle, F = 0.955 X Units T X Units N t X What is the strength of the magnetic field if I = 2.5 A and 1 = 11 cm? The magnetic field, B = ✓✓. Part 1 of 2 Part 2 of 2A 6.70 -μC particle moves through a region of space where an electric field of magnitude 1250 N/C points in the positive a direction, and a magnetic field of magnitude 1.25 T points in the positive z direction. Part A If the net force acting on the particle is 6.23x10-³ N in the positive direction, find the components of the particle's velocity. Assume the particle's velocity is in the x-y plane. Enter your answers numerically separated by commas. IVE ΑΣΦ Vz, Vy, Uz = ? m/sA particle with initial velocity vo (5.85 × 10³ m/s) enters a region of uniform electric and magnetic fields. The magnetic field in the region is B = -(1.35T)k. You can ignore the weight of the particle. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of An e,m demonstration experiment. Part A Calculate the magnitude of the electric field in the region if the particle is to pass through undeflected, for a particle of charge +0.640 nC. Express your answer in volts per meter. E = Submit Part B Part C ΑΣΦ E = Request Answer ? V/m Calculate the magnitude of the electric field in the region if the particle is to pass through undeflected, for a particle of charge -0.320 nC. Express your answer in volts per meter. 17 ΑΣΦ V/m
- A particle with charge 9.78 x 10^-6 C moves at 8.62 x 10^6 m/s through a magnetic field of strength 1.18 T. The angle between the particle s velocity and the magnetic field direction is 40.5 degrees and the particle undergoes an acceleration of 16.0 m/s^2. What is the particle s mass?A particle with charge 2.50 µC and mass 3.00x10-11 kg is initially traveling in the +y-direction with a speed vo = 1.60x105 m/s. It then enters a region containing a uniform magnetic field that is directed into, and perpendicular to, the page in the figure (Figure 1). The magnitude of the field is 0.450 T. The region extends a distance of 25.0 cm along the initial direction of travel; 75.0 cm from the point of entry into the magnetic field region is a wall. The length of the field- free region is thus 50.0 cm. When the charged particle enters the magnetic field, it follows a curved path whose radius of curvature is R. It then leaves the magnetic field after a time t1, having been deflected a distance Az1. The particle then travels in the field-free region and strikes the wall after undergoing a total deflection Ar. Part C Determine Az1, the horizontal deflection at the point of exit from the field. Express your answer in meters. Π ΑΣφ. ? Ar1 = Submit Previous Answers Request Answer…Please help with parts B and C
- A proton moves with a velocity of v= (2î − 5ĵ + k) m/s in a region in which the magnetic field is B= (î + 2ĵ − k) T. What is the magnitude of the magnetic force this particle experiences? NN batteries not shown A. A wire is connected to batteries (not shown), and current flows through the wire. The wire lies flat on a table, and you are looking down on it from above. The wire is laid on top of a compass, resting about 6 mm above the needle. The distance d is 5.5 cm. The compass needle deflects 11 degrees from North, as shown. At this location the horizontal component of the Earth's magnetic field is 2e-5 tesla. What is the direction of the magnetic field at location A, midway between the wires, due to the current in the wire? Out of the page What is the approximate magnitude of the magnetic field at location A, due to the current in the wire? |B| = 3.88e-6 × T What approximations or assumptions did you make in solving this problem? Assume one side of the wire is much longer than d Assume that at the location of the compass the effect of the distant wire is negligible Assume the Earth's magnetic field is negligible Assume the bent end of the wire is far from location AE A charge of 1.1 C having an initial velocity of 3.91+4.1k m/s enters a region with an electric field E=3.4k N/C and a magnetic field B=4.27+3.9k T. Calculate the magnitude of the force on the charge immediately after it enters the region. Express your answer in Newtons (write just the value, not the unit), rounding to one digit after the decimal separator. Yanitinizi ekleyin.