A telephone pole has been knocked over by the wind so that it makes an angle of theta= 15 degrees with the vertical. The wind has stopped blowing and the pole is to be cut down. Once the cut is across most of the thickness of the pole, the pole begins to tip over. As the pole tips, the bottom of the pole stays attached to the base by the remaining part of the pole that was not cut (but the torque from the base on the tipping pole is negligible). There is a nail (of negligible mass) on the pole located a distance x = 47 m from the cut. The length of the pole from the cut to the top is L=69m. Remember that the moment of inertia of a stick of mass m and length L about its end is (13)mL2. If theta= 67.5 degrees, what is the magnitude of the angular acceleration of the nail?
A telephone pole has been knocked over by the wind so that it makes an angle of theta= 15 degrees with the vertical. The wind has stopped blowing and the pole is to be cut down. Once the cut is across most of the thickness of the pole, the pole begins to tip over. As the pole tips, the bottom of the pole stays attached to the base by the remaining part of the pole that was not cut (but the torque from the base on the tipping pole is negligible). There is a nail (of negligible mass) on the pole located a distance x = 47 m from the cut. The length of the pole from the cut to the top is L=69m. Remember that the moment of inertia of a stick of mass m and length L about its end is (13)mL2. If theta= 67.5 degrees, what is the magnitude of the angular acceleration of the nail?
A telephone pole has been knocked over by the wind so that it makes an angle of theta= 15 degrees with the vertical. The wind has stopped blowing and the pole is to be cut down. Once the cut is across most of the thickness of the pole, the pole begins to tip over. As the pole tips, the bottom of the pole stays attached to the base by the remaining part of the pole that was not cut (but the torque from the base on the tipping pole is negligible). There is a nail (of negligible mass) on the pole located a distance x = 47 m from the cut. The length of the pole from the cut to the top is L=69m. Remember that the moment of inertia of a stick of mass m and length L about its end is (13)mL2. If theta= 67.5 degrees, what is the magnitude of the angular acceleration of the nail?
A telephone pole has been knocked over by the wind so that it makes an angle of theta= 15 degrees with the vertical. The wind has stopped blowing and the pole is to be cut down. Once the cut is across most of the thickness of the pole, the pole begins to tip over. As the pole tips, the bottom of the pole stays attached to the base by the remaining part of the pole that was not cut (but the torque from the base on the tipping pole is negligible). There is a nail (of negligible mass) on the pole located a distance x = 47 m from the cut. The length of the pole from the cut to the top is L=69m. Remember that the moment of inertia of a stick of mass m and length L about its end is (13)mL2. If theta= 67.5 degrees, what is the magnitude of the angular acceleration of the nail?
Definition Definition Rate of change of angular velocity. Angular acceleration indicates how fast the angular velocity changes over time. It is a vector quantity and has both magnitude and direction. Magnitude is represented by the length of the vector and direction is represented by the right-hand thumb rule. An angular acceleration vector will be always perpendicular to the plane of rotation. Angular acceleration is generally denoted by the Greek letter α and its SI unit is rad/s 2 .
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