A system with a 16M x 8 main memory has an 8G x 4K virtual memory and will require ___ bits for each virtual address, ___ bits for each physical address, and ___ bits for the offset in both addresses.
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A system with a 16M x 8 main memory has an 8G x 4K virtual memory and will require ___ bits for each virtual address, ___ bits for each physical address, and ___ bits for the offset in both addresses.
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- If a microprocessor has a cycle time of 0.5 nanoseconds, what’s the processor clock rate? If the fetch cycle is 40% of the processor cycle time, what memory access speed is required to implement load operations with zero wait states and load operations with two wait states?Processor R is a 64-bit RISC processor with a 2 GHz clock rate. The average instruction requires one cycle to complete, assuming zero wait state memory accesses. Processor C is a CISC processor with a 1.8 GHz clock rate. The average simple instruction requires one cycle to complete, assuming zero wait state memory accesses. The average complex instruction requires two cycles to complete, assuming zero wait state memory accesses. Processor R can’t directly implement the complex processing instructions of Processor C. Executing an equivalent set of simple instructions requires an average of three cycles to complete, assuming zero wait state memory accesses. Program S contains nothing but simple instructions. Program C executes 70% simple instructions and 30% complex instructions. Which processor will execute program S more quickly? Which processor will execute program C more quickly? At what percentage of complex instructions will the performance of the two processors be equal?A memory system has 4 KB byte-addressable main memory and a direct-mapped cache that consists of 8 blocks with 16 bytes per block. The following shows the main memory address format that allows us to map addresses from main memory to cache. Note: 12 bit address, 4 bit offset, 3 bit $block, and 5 bit tag Assume the cache directory shown below:
- An operating system designed for an embedded system application needs to manage a process of size 512KB with a page size of 8KB. If the memory size is 256KB then answer the following questions - a) Determine the minimum number of bits required to manage the logical address space. b) Determine the minimum number of bits required to manage the physical address space.What distinguishes a 7CH bit address from a 7CH byte address? Where in memory does bit address 7CH reside?A small computer system has 64KB virtual address space and 32KB physical address space as shown in Fig. B. The page size is 4KB (4096 bytes). Virtual address space 60K-64K 56K-60K Virtual page 52K-56K 48K-52K 44K-48K 7 40K-44K Physical 36K-40K memory address 32K-36K 28K-32K 28K-32K 24K-28K 24K-28K 20K-24K 3 20K-24K 16K-20K 4 16K-20K 12K-16K 12K-16K 8K-12K 8K-12K 4K-8K 1 | 4K-8K OK-4K 2 OK-4K Page frame Fig. B What is the physical address for the following virtual addresses? (1) 3000 (2) 4200 (3) 9000 (4) 24000
- Suppose a computer using fully associative cache has 216 bytes of byte-addressable main memory and a cache of 64 blocks, where each cache block contains 32 bytes.Q.) To which cache block will the memory address 0xF8C9 map?Virtual memory requires a physical addresses A to map virtual addresses to actualWhat is the difference between a 7CH bit address and a 7CH byte address? Where in memory does bit address 7CH reside?
- An 8-bit computer has a 16-bit address bus. The first 15 lines of the address are used to select a bank of 32K bytes of memory. The high-order bit of the address is used to select a register which receives the contents of the data bus. Explain how this configuration can be used to extend the memory capacity of the system to eight banks of 32K bytes each, for a total of 256K bytes of memory.A computer has a 16 bit address space A[15:0]. If all addresses having bits A[15:14]=11 are reserved for I/O device registers, then the maximum number of actual word addressable memory locations is 216 - 214 Group of answer choices True FalseSuppose that a 64M x 16 main memory is built using 512K × 8 RAM chips and memory is word-addressable. a) How many RAM chips are necessary?b) If we were accessing one full word, how many chips would be involved?c) How many address bits are needed for each RAM chip?d) How many banks will this memory have?e) How many address bits are needed for all of memory?f) If high-order interleaving is used, where would address 32(base 10) be located? (Your answer should be "Bank#, Offset#")g) Repeat (f) for low-order interleaving.