> f1 (1) [1] 2 < > f1(2) [1] 3
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3 Write two different functions which have the following results with input 1 and 2. It means that these two different functions are equivalent at input 1 and input 2.
![> f1 (1)
[1] 2
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> f1(2)
[1] 3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F580cd851-1115-453f-9bd6-403175e6d071%2Ff4071f9d-d6b2-4a31-a55f-34f3177ecd52%2F3lrh16_processed.jpeg&w=3840&q=75)
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- Explain the concept of lazy loading and its application in optimizing data binding performance.int machineCompare1(struct machine* mac1, struct machine* mac2){ struct mac1; struct mac2; char make1[21], make2[21]; char model1[51], model2[21]; if((lap1 -> make1 == lap2 -> make2) && (lap1 -> model1 == lap2 -> model2)) return 0; else return 1;} have to create function to compare make and model of 2 machines - it's using structures - not sure if this is correct/ on the right track?1. Please explain in detail Scott Meyers’s point: Use weak_ptr for shared_ptr like pointers that can dangle. 2. How are Smart Pointer functions move(), reset(), and release() different from each other? Please also explain in detail which function is most dangerous and why? 3. Please explain in detail how to manually destroy an existing Smart Pointer control block.
- typedef struct { short data[4];} MatrixElement; void copy_matrix(MatrixElement m1[], MatrixElement m2[], int ROWS, int COLS) { int i, j, k; for (i = 0; i < ROWS; i++) { for (j = 0; j < COLS; j++) { for (k = 0; k < 4; k++) { m1[i*COLS+j].data[k] = m2[i*COLS+j].data[k]; } } }} void copy_matrix_transpose(MatrixElement m1[], MatrixElement m2[], int ROWS, int COLS) { int i, j, k; for (i = 0; i < ROWS; i++) { for (j = 0; j < COLS; j++) { for (k = 0; k < 4; k++) { m1[i*COLS+j].data[k] = m2[j*ROWS+i].data[k]; } } }} You can assume the following conditions: The matrix m1 is allocated at memory address 0, and matrix m2 immediately follows it. Indices i, j, and k are kept in registers. ROWS and COLS are constants. The cache is initially empty before the function call. The cache is write-back (i.e., only writes back to memory when a line is…Function Implementation with Data Abstraction in C Programming 1. Create a new file and SAVE as MATHV1.H Define and Implement the following functions: int sum(int x, int y); - returns the computed sum of two numbers x and y int diff(int x, int y); - returns the computed difference of two numbers x and y. Make sure that the larger number is deducted by the smaller number to avoid a negative answer long int prod(int x, int y); - returns the computed product of two number x and y float quot(int x, int y); - returns the computed quotient of two numbers x and y. Make sure that the larger number is always the numerator and divided by the smaller number to avoid division by zero error. int mod(int x, int y); - returns the computed remainder of two numbers x and y using the modulo operator %2. Create another new file and save as MYTOOLS.H void center(int row, char str[]); /*centers text across the screen -calculate here for the center col using the formula col=(80-strlen(str))/2; -then use…Define global pointer.
- Hef sharks_minnows (minnows, sharks): shark_count = 0 minnow_count = len (minnows) for i in range(minnow_count): curr_shark_height = minnows [i] if curr_shark_height is not None: minnows [i] = None for j in range (i + 1, minnow_count): if minnows [j] == curr_shark_height: minnows [j] = None curr_shark_height -- 1 shark_count += 1 return shark_count <= sharks The provided code is imperfect, in that it sometimes returns True when it should return False, and sometimes returns False when it should return True. (a) Provide an example of a function call where the provided code will correctly return True (i.e. a True Positive) (b) Provide an example of a function call where the provided code will correctly return False (i.e. a True Negative) (c) Provide an example of a function call where the provided code will incorrectly return True (i.e. a False Positive) (d) Provide an example of a function call where the provided code will incorrectly return False (i.e. a False Negative)4. O] The abstract data type (ADT) Set(Elm) represent sets. Accordingly, the following is a possible set of operators: new: Set in Set Elm → Bool empty Set → Bool count Set Integer add Set Elm → Set delete Set Elm → Set intersect Set x Set union Set × Set → Set create a new, empty set true iff a value is in a set true is the set is empty returns the number of values in the set adds a value to a set removes a value from a set Set returns the intersection of two sets returns the union of two sets (a) [5] Identify between the operators enumerated above a minimal set of constructors and justify your choice (b) [5] Provide axioms for the operators empty, count, and delete.Consider the following C++ code segment: int d = 20; int f(int b) { static int c = 0; c *= b; return c; } int main() { int a; cin >> a; cout << f(a) * d << endl; } For each variable a, b, c, d: identify all type bindings and storage bindings (for each binding, determine when the binding occurs) Then the scope of each variable.
- PLEASE USE THESE CODES FOR SOLVİNG C QUESİTON typedef struct LINKED_STACK_NODE_s *LINKED_STACK_NODE;typedef struct LINKED_STACK_NODE_s{ LINKED_STACK_NODE next; void *data;} LINKED_STACK_NODE_t[1]; typedef struct LINKED_STACK_s{ LINKED_STACK_NODE head;} LINKED_STACK_t[1], *LINKED_STACK; // Creates and initializes a linked stack and returns its pointerLINKED_STACK linked_stack_init(){ LINKED_STACK new; new = (LINKED_STACK) malloc(sizeof(LINKED_STACK_t)); if (new !=NULL) { new->head = NULL; else { printf("problem cannot allocate memory"); } return new; } // Deallocates the memory allocated by the stackvoid linked_stack_free(LINKED_STACK stack){ while(stack->head !=NULL) { linked_stack_pop(stack);}free(stack);} // Pushes data into the stack following FIFO principlevoid linked_stack_push(LINKED_STACK stack, void *data){ LINKED_STACK_NODE node = (LINKED_STACK_NODE)malloc(sizeof(LINKED_STACK_NODE_t)); if(node != NULL) {…Programming Languages Pragmatics, 4th EditionConsider the following C++ code segment: int d = 20; int f(int b) { static int c = 0; c *= b; return c; } int main() { int a; cin >> a; cout << f(a) * d << endl; }For each variable a, b, c, d: identify all type bindings and storage bindings for each binding, determine when the binding occurs identify the scope and lifetime