A system has four processes and five allocatable resources. The current allocation and maximum needs are as follows: Allocated Махітит Available Process A 10211 11213 00x11 Process B 20110 22210 Process C 11010 21310 Process D 11110 11221
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- 1. Consider a real-time system in which there are five tasks. Their period and execution time are as follows: Task Execution Time Period T1 10 200 T2 25 150 T3 45 100 T4 15 75 T5 20 50 Perform EDF Scheduling on these task set.The current allocation and maximum needs of a system having four processes and five allocated resources are shown as follows. What is the smallest value of x for which this is a safe state? Allocated Maximum Available Process A Process B Process C Process D O 010 1 2 3 1021111213 00 x 12 2011022210 11010 21310 11110 11221Downvote for incorrect answer. Likes for correct ones
- Suppose that a multiprogrammed system has a load of N processes with individual execution times of t1, t2, ...,tN. Answer the following questions: a) How would it be possible that the time to complete the N processes could be as small as: maximum (t1, t2, ...,tN)? b) How would it be possible that the total execution time, T > t1+ t2+ ...+tN? In other words, what would cause the total execution time to exceed the sum of individual process execution times?A system contains five tasks. There are three resources X, Y, and Z. The resource requirements of the tasks are specified as follows: T: [X; 1] [Y; 2]. T;: [Z; 4]. T3: [X; 2]. T4: [X, 2][Y; 3]. T3: [X; 1] [Z; 3]. The tasks are indexed in the decreasing order of priorities and scheduled with the priority ceiling protocol. Find the maximum blocking time for each task.Note: Write a C Language program:
- Modern Operating Systems must tackle the challenges of Synchronization and Deadlock. 'Pro- vess Synchronization' is the task of coordinating the execution of processes in a way that no two processes can have access to the same shared data or resource. A process requesting a resource may have to wait, if the resource is not available at that time. Sometimes, a waiting process is never able to change state, because the resources it has requested are held by other waiting processes; this situation is called 'Deadlock'. ,In concurrent programming, a "critical section" is a part of a multi-process program that (a) may not be concurrently executed by more than one of the program's thread. Let us consider a 2 processes solution: do { flag(i] - TRUE; while (flag[j]); %wait CRITICAL SECTION flag[i] - FALSE; REMAINDER SECTION } while (TRUE); Pseudo-code of $P_i$ (the one of $P_j$ is symmetric) (i) { simple 'yes-no' answer is NOT enough. What is the mutual exclusion requirement? Why is (not?)…The most effective method of process scheduling has been shown to beAn operating system uses Shortest Remaining Time first (SRT) process scheduling algorithm. Consider the arrival times and execution times for the following processes: Process Execution time Arrival time P1 20 P2 25 15 P3 10 30 P4 15 45 What is the total waiting time for process P2?
- A single-CPU system has four processes, P1, P2, P3 and P4 in the ready queue. The execution times and I/O needs for these processes are given below. All times are in ms. (hint: when a process starts an IO operation, it is removed from the ready queue and put back at the end of the queue only when it completes its IO). Process P1: Arrives at 0ms, needs 23ms of CPU time. Performs I/O for 5ms after 10ms of its execution time, then another 5ms after 20ms of its execution time. Process P2: Arrives at 3ms, needs 12ms of CPU time. Performs I/O for 10ms after 5ms of its execution time. Process P3: Arrives at 1ms, needs 15ms of CPU time. Performs I/O for 1ms after 7ms of its execution time. Process P4: Arrives at 2ms, needs 8ms of CPU time. Performs I/O for 5ms after 4ms of its execution time. We assume that the CPU is idle if no one of these four processes is using it. Using Round Robin scheduling algorithm with a Time Quantum of 4ms and ignoring the context switch time, determine: a) The…Suppose that each of the 4 processors in a shared memory multi-processor system is rated at 400 MIPS. A program contains a purely sequential part that accounts for 22% of the program’s execution time on a single processor. The remaining code can be partitioned into three independent parts (A, B, and C). Running on a single processor, part A accounts for 30% of the program’s execution time, part B accounts for 18%, and part C accounts for 30%. What is the apparent MIPS rating for the program if it is run on the 4-processor system and the sequential part must be completed before any of the remaining independent parts (A, B or C) can run in parallel?Course: Operating Systems Given below is the pseudocode to synchronize processes P1, P2, P3, P4, P5, and P6 byusing three semaphores X, Y and Z that are initialized as follow: X=0, Y=0, Z= –2. TheOperating System can schedule the processes which are ready to execute in any order.List down at least 5 possible orders of execution in which the processes can run.