A system does 501 kJ of work and loses 216 kJ of heat to the surroundings. What is the change in internal energy, AE, of the system? Note that internal energy is symbolized as AU in some sources. ΔΕ- kJ

Chemistry for Engineering Students
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Chapter9: Energy And Chemistry
Section: Chapter Questions
Problem 9.11PAE: 9.11 Analyze the units of the quantity (pressurevolume) and show that they are energy units,...
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**Problem Statement:**

A system does 501 kJ of work and loses 216 kJ of heat to the surroundings. What is the change in internal energy, ΔE, of the system? Note that internal energy is symbolized as ΔU in some sources.

**Calculation:**

ΔE = [Input your answer here] kJ

---

**Explanation:**

This problem involves calculating the change in internal energy for a system based on the First Law of Thermodynamics. The formula to use is:

ΔE = Q - W

Where:
- ΔE is the change in internal energy.
- Q is the heat exchanged.
- W is the work done by the system.

Plug in the given values:
- Q = -216 kJ (since the system loses heat, it is negative)
- W = 501 kJ 

Calculate ΔE using the formula provided.
Transcribed Image Text:**Problem Statement:** A system does 501 kJ of work and loses 216 kJ of heat to the surroundings. What is the change in internal energy, ΔE, of the system? Note that internal energy is symbolized as ΔU in some sources. **Calculation:** ΔE = [Input your answer here] kJ --- **Explanation:** This problem involves calculating the change in internal energy for a system based on the First Law of Thermodynamics. The formula to use is: ΔE = Q - W Where: - ΔE is the change in internal energy. - Q is the heat exchanged. - W is the work done by the system. Plug in the given values: - Q = -216 kJ (since the system loses heat, it is negative) - W = 501 kJ Calculate ΔE using the formula provided.
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