A synthetic fiber used in manufacturing carpet has tensile strength that is normally distributed with mean 75.5 psi and standard deviation 3.5 psi. Find the probability that a random sample of n = 6 fiber specimens will have sample mean tensile strength that exceeds 75.75 psi. With solution please, thank you
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2.) A synthetic fiber used in manufacturing carpet has tensile strength that is
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- A synthetic fiber used in manufacturing carpet has tensile strength that is normally distributed with mean 75.5 psi and standard deviation 3.5 psi. How is the standard deviation of the sample mean changed when the sample size is increased from n = 4 ton = 48 Round all intermediate calculations to four decimal places (e.g. 12.3456) and round the final answer to three decimal places (e.g. 98.768). The standard deviation is reduced ✓by i 1.25 psi. Statistical Tables and ChartsIf bone density is normally distributed with 0 for the mean and 1 for the standard deviation, what is the probaility that a population has a bone density between the z scores of -0.84 and 1.2?The tensile strength of steel bars produced by a manufacturer has a mean 30 MPa and the [10] standard deviation of 1.5MPa. By a new technique in the manufacturing process, it is claimed that the tensile strength can be improved. To test this claim, a sample of 50 steel bars is tested and it is found that the mean tensile strength is 30.5MPa. Can we support the claim at 0.01 level of significance?
- Iron plates are required to have a certain thickness but each plate produced will differ slightly from each other due to properties of the material and uncertainties in the behaviour of the machines that make them. Let X be the plate thickness in mm of plates produced by a given machine. Using the machine's default setting, X follows a normal distribution with mean 12mm and standard deviation 1.5mm (a) What percentage of plates should be expected to be thinner than 10 mm? (b) What percentage of plates should be expected to be thicker than 15mm?Height and weight are two measurements used to track a child's development. An organization measures child development by comparing the weights of children who are the same height and the same gender. In a certain year, weights for all 80 cm girls in the reference population had a mean ? = 11.8 kg and standard deviation ? = 0.6 kg. Weights are normally distributed. X ~ N(11.8, 0.6). Calculate the z-scores that correspond to the following weights and interpret them. (Round your numerical answers to two decimal places.) (a) 12.4 kg z = _______ A child who weighs 12.4 kg is standard deviation(s) [above/below] the mean of 11.8 kg. (b) 10.1 kg z = _______ A child who weighs 10.1 kg is standard deviation(s) [above/below] the mean of 11.8 kg. (c) 13.3 kg z = ________ A child who weighs 13.3 kg is standard deviation(s) [above/below] the mean of 11.8 kg.The Null would be accepted is that correct? 6. State the null hypothesis for variation in central-to-peripheral fat ratio (kg) from baseline to 12 months for the TCu 380A IUD group. Should the null hypothesis be accepted or rejected?
- The average number of miles a person drives per day is 24. A researcher wishes to see if people over age 60 drive less than 24 miles per day. She selects a random sample of 40 drivers over the age of 60 and finds that the mean number of miles driven is 22.7. The population standard deviation is 2.9 miles. At =α0.01, is there sufficient evidence that those drivers over 60 years old drive less than 24 miles per day on average? Assume that the variable is normally distributed. Use the critical value method with tables. State the hypotheses and identify the claim with the correct hypothesis.To determine if their 1.33 centimeter galvanized pipes are properly adjusted, Fogarty Manufacturing has decided to use an X-Chart which uses the range to estimate the variability in the sample. Answer How to enter your answer Step 3 of 7: What is the Lower Control Limit? Round your answer to three decimal places. 1 ~ 3 Sample Mean Sample Range 1.33 1.3320 1.29 1.38 1.3300 Period obs1 obs2 obs3 obs4 obs5 1.34 1.29 1.35 2 1.35 1.35 3 1.34 1.35 1.36 1.29 1.29 1.31 1.32 1.33 1.34 1.3360 1.35 1.30 1.3340 1.32 1.38 1.3260 1.37 1.33 1.31 1.31 1.29 1.30 1.35 1.31 1,32 1.34 1.38 8 1.35 1.33 1.31 1.34 1.3180 1.33 1.3300 1.34 1.37 1.28 1.36 9 10 1.32 1.37 1.30 1.37 1.29 1.32 1.30 1.28 1.29 11 1.35 1.36 1.38 12 1.36 1.32 1.31 1.30 1.35 13 1.29 1.35 1.32 1.32 1.37 1.35 1.35 1.34 1.32 1.34 14 15 1.32 1.36 1.29 1.32 1.35 45 Table 67 Control Chart 1.35 1.28 Copy Table Average Values The average of the selected cell(s) is 1.340. Copy Value 1.3300 1.3440 1.3080 1.3400 1.3280 1.3300 1.3400 1.3280 0.06…Please show complete and clear solution! Last 45 minutes left Thank you!
- SOLVE FOR CRITICAL VALUE Two suppliers manufacture a plastic gear used in a laser printer. The impact strength of these gears measures in foot-pounds is an important characteristic. A random sample of 10 gears from supplier 1 results in x1 = 290 and s1 = 12 while another random sample of 16 gears from the second supplier results in x2 = 321 and s2 = 22. Is there evidence to support the claim that supplier 2 provides gears with higher mean impact strength. Use a =0.04, and assume that both populations are normally distributed with equal variances.Level of significance = 0.04A population of values has a normal distribution with u = 94.8 and o = 16. You intend to draw a random sample of sizen = 76. Find the probability that a sample of size n = 76 is randomly selected with a mean greater than 100.3. P(M > 100.3) = Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or z- Scores rounded to 3 decimal places are accepted. Submit Question % & 3 4. 7 9. e y 00 %24 CUDaily Driving The average number of miles a person drives per day is 24. A researcher wishes to see if people over age 60 drive less than24 miles per day. She selects a random sample of 25 drivers over the age of 60 and finds that the mean number of miles driven is 23.4. The population standard deviation is 4.1 miles. At=α0.01, is there sufficient evidence that those drivers over 60 years old drive less than 24 miles per day on average? Assume that the variable is normally distributed. Use the critical value method with tables. State the hypotheses and identify the claim with the correct hypothesis. :H0 =μ24 ▼not claim :H1 <μ24 ▼claim the hypothesis test is a ▼one-tailed test. Part 2 of 5 Find the critical value(s). Round the answer to at least two decimal places. If there is more than one critical value, separate them with commas. Critical value(s):