The thickness (in millimeters) of the coating applied to hard drives is one characteristic that determines the usefulness of the product. When no unusual circumstances are present, the thickness (x) has a normal distribution with a mean of 5 mm and a standard deviation of 0.02 mm. Suppose that the process will be monitored by selecting a random sample of 16 drives from each shift's production and determining x, the mean coating thickness for the sample. USE SALT (a) Describe the sampling distribution of x for a random sample of size 16. The distribution of x is normal with mean 5 standard deviation 0.005 mm. mm and (b) When no unusual circumstances are present, we expect x to be within 30 of 5 mm, the desired value. An x value farther from 5 mm than 30 is interpreted as an indication of a problem that needs attention. Calculate 5 + 30% 5-30 = 4.985 mm 5 + 30x = 5.015 mm (c) Referring to part (b), what is the probability that a sample mean will be outside 5 ± 30 just by chance (that is, when there ar no unusual circumstances)? (Round your answer to four decimal places.) 0.9973 x (d) Suppose that a machine used to apply the coating is out of adjustment, resulting in a mean coating thickness of 5.02 mm. What is the probability that a problem will be detected when the next sample is taken? (Hint: This will occur if x > 5 + 30 or x < 5 - 30x when μ = 5.02. Round your answer to four decimal places.) 0.0027 X

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The thickness (in millimeters) of the coating applied to hard drives is one characteristic that determines the usefulness of the
product. When no unusual circumstances are present, the thickness (x) has a normal distribution with a mean of 5 mm and a
standard deviation of 0.02 mm. Suppose that the process will be monitored by selecting a random sample of 16 drives from each
shift's production and determining x, the mean coating thickness for the sample.
USE SALT
(a) Describe the sampling distribution of x for a random sample of size 16.
The distribution of x is normal
with mean 5
standard deviation 0.005
mm.
4.985
5.015
mm and
(b) When no unusual circumstances are present, we expect x to be within 30 of 5 mm, the desired value. An x value farther from
5 mm than 30 is interpreted as an indication of a problem that needs attention. Calculate 5 ± 30%
mm
5 - 30%
mm
5 + 30 x
(c) Referring to part (b), what is the probability that a sample mean will be outside 5 ± 30 just by chance (that is, when there are
no unusual circumstances)? (Round your answer to four decimal places.)
0.9973
X
(d) Suppose that a machine used to apply the coating is out of adjustment, resulting in a mean coating thickness of 5.02 mm.
What is the probability that a problem will be detected when the next sample is taken? (Hint: This will occur if x > 5 + 30x or
x < 5 - 30x when μ = 5.02. Round your answer to four decimal places.)
0.0027
X
Transcribed Image Text:The thickness (in millimeters) of the coating applied to hard drives is one characteristic that determines the usefulness of the product. When no unusual circumstances are present, the thickness (x) has a normal distribution with a mean of 5 mm and a standard deviation of 0.02 mm. Suppose that the process will be monitored by selecting a random sample of 16 drives from each shift's production and determining x, the mean coating thickness for the sample. USE SALT (a) Describe the sampling distribution of x for a random sample of size 16. The distribution of x is normal with mean 5 standard deviation 0.005 mm. 4.985 5.015 mm and (b) When no unusual circumstances are present, we expect x to be within 30 of 5 mm, the desired value. An x value farther from 5 mm than 30 is interpreted as an indication of a problem that needs attention. Calculate 5 ± 30% mm 5 - 30% mm 5 + 30 x (c) Referring to part (b), what is the probability that a sample mean will be outside 5 ± 30 just by chance (that is, when there are no unusual circumstances)? (Round your answer to four decimal places.) 0.9973 X (d) Suppose that a machine used to apply the coating is out of adjustment, resulting in a mean coating thickness of 5.02 mm. What is the probability that a problem will be detected when the next sample is taken? (Hint: This will occur if x > 5 + 30x or x < 5 - 30x when μ = 5.02. Round your answer to four decimal places.) 0.0027 X
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