The score on a standardized test for a certain year is modeled using the normal distribution shown below. The mean of the distribution is 56.7 points and the standard deviation is 4.8 points. In the figure, V is a number along the axis and is under the highest part of the curve. And, U andW are numbers along the axis that are each the same distance away from V. Use the empirical rule to choose the best value for the percentage of the area under the curve that is shaded, and find the values U, V, and W. Percentage of total area shaded: 99.7% 55 0 70 0 75 60 65 40 45 50
The score on a standardized test for a certain year is modeled using the normal distribution shown below. The mean of the distribution is 56.7 points and the standard deviation is 4.8 points. In the figure, V is a number along the axis and is under the highest part of the curve. And, U andW are numbers along the axis that are each the same distance away from V. Use the empirical rule to choose the best value for the percentage of the area under the curve that is shaded, and find the values U, V, and W. Percentage of total area shaded: 99.7% 55 0 70 0 75 60 65 40 45 50
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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Transcribed Image Text:The score on a standardized test for a certain year is modeled using the normal distribution shown below.
The mean of the distribution is 56.7 points and the standard deviation is 4.8 points.
In the figure, V is a number along the axis and is under the highest part of the curve.
And, U and W are numbers along the axis that are each the same distance away from V.
Use the empirical rule to choose the best value for the percentage of the area under the curve that is shaded, and find the values of
U, V, and W.
Percentage of total area shaded: 99.7%
55 0
60
65
70 0
40
45
50
75
Test score
Explanation
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