A symmetrical parabolic summit curve connects two grades of +5.7% and -49%. It is to pass through a point D" on the curve at station 25+180m. If the stationing of the grade intersection is 25+145m and the stationing of PVC is 24+976m, determine the following: Length of the parabolic curve Stationing of the highest point. [VALUE ONLY/DON'T PUT PLUS(+) SIGN] Difference in elevation between PVC and PVI Difference in elevation between PVC and point D

A symmetrical parabolic summit curve connects two grades of +5.7% and -49%. It is to pass through a point D" on the curve at station 25+180m. If the stationing of the grade intersection is 25+145m and the stationing of PVC is 24+976m, determine the following: Length of the parabolic curve Stationing of the highest point. [VALUE ONLY/DON'T PUT PLUS(+) SIGN] Difference in elevation between PVC and PVI Difference in elevation between PVC and point D

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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7. A -3% grade meets a +5% grade near an underpass. In order to maintain the minimum clearance allowed under the bridge and at the same time introduce a vertical transitioning curve in the grade line, it is necessary to use a curve that lies 200-m on one side of the vertex of the straight grade and 100-m on the other. The stationing of the beginning of the curve (200-m side) is 10+000 and elevation is 228m. a.) Determine the stationing of the lowest point of the curve. b.) Determine the elevation at STA 10+040. c.) If the uphill edge of the underside of the bridge is at station 10+220 and at elevation 229.206m, what is the vertical clearance under the bridge at this point?
6. A vertical parabolic curve has a back tangent of -5% and a forward tangent of +3% intersecting at station 1+240 at an elevation of 100.00m. If the stationing of PC is at 1+120, a.) Evaluate the stationing at the lowest point of the curve. b.) Evaluate the elevation of the lowest point in the curve. c.) Evaluate the grade at the first quarter point. d.) Evaluate the elevation at the third quarter point. e.) Evaluate the rate of change of grade of the sag curve per 20m length.
Two tangents intersect at V with back tangent having a grade of -4.5% and forward tangent of 5.5%. A 200 m curve lies on the side of PC and 102.5 on the other side. Stationing of V is at 10+538 having an elevation of 104 m. If a bridge is located above the curve, with its centerline having an elevation of 118.5 m and stationing of 10+555, with underside of the bridge located 55 cm below the given elevation, determine the height of highest vehicle it can accommodate if the bridge has a width of 12 m.
Design the curve, of An equal tangent vertical curve is to be constructed between grades of -2.0% (initial) and 1.0% (final). The PVI is at station 11 + 000.000 and at elevation 420 m. Due to a street crossing the roadway, the elevation of the roadway at station 11 + 071.000 must be at 421.5 m. GIVEN DIMENSIONS ON THE ATTACHED PICTURE
B. A Highway curve will pass through a railway at grade. The crossing must be at Sta. 4 + 310 and at elevation 220.82 m. the initial grade is +2% and meets a -3% grade at Sta. 4 + 235 at an elevation of 223.38 m. the rate of change must not exceed at 2%. Compute the length of curve, station and elevation of highest point also check if the condition of rate of change is meet.
A symmetrical parabolic summit curve connects two grades of +6% and -4%. It is to pass though a point "P" the stationing of which is 35+280 and the elevation is 193.13 meters. If the elevation of the grade intersection is 200 m with stationing 35 + 300. 1. What is the length of the curve? a. 120 m b. 123 m c. 121 m d. 122 m
Two tangents intersect at V with back tangent having a grade of -4.5% and forward tangent of 5.5%. A 200 m curve lies on the side of PC and 102.5 on the other side. Stationing ofV is at 10+538 having an elevation of 104 m. If a bridge is located above the curve, with its centerline having an elevation of 118.5 m and stationing of 10+555, with underside of the bridge located 55 cm below the given elevation, determine the height of highest vehicle it can accommodate if the bridge has a width of 12 m.
3.9 An equal-tangent crest curve connects a +2% initial grade with a -1% final grade, and is designed for 55 mi/h. The station of the PVI is 233 + 40 with elevation 1203 ft. What is the elevation of the curve at station 234 +00?
Note : If you don't know the solution please leave it but don't give me wrong solution. A vertical curve joining entering grade of -4% with an exiting grade of - 7% begins at station 2+607 and is being designed with K value of 72. What is the station of the highest point on the curve . Code the station as the total distance from the origin, i.e., if the station is 1+100 code it as 1100.
2. A symmetrical sag curve has a descending grade of -4.2% and an ascending grade of +2.5% intersecting at Station 10+120, whose elevation is 382.3÷4 m. The rate of change of grade is restricted to 0.60%. a. What is the vertical offset of the parabolic curve to the point of intersection of the tangent grades? b. At what distance from PC is the lowest point of the curve located?
Note: Solve and draw
A grade of -3.6% is followed by a grade of +2.1% which intersects at station 10+256 and elevation of 116 m. If the maximum change in grade per 20 m station is 0.20%, determine the following A. Length of parabolic curve that shall connect these two grade lines. B. Elevation of PC. C. Elevation of a point on the curve @ Sta.10+250.