A symmetrical beam of length 300 mm is loaded with a force of 414 N downwards (positive z) and has the following equation for the vertical displacement: w (2) = , ( - +) 48 The value of E is 200,000 Nmm²² and the values of ly is 20x 106 mm“ The maximum value of z for the beam cross section is ±20 mm What is the maximum tensile stress in the beam at the point when x = 90 mm? Express your answer in Nmm2, as a number to 2 dp, without the units.
A symmetrical beam of length 300 mm is loaded with a force of 414 N downwards (positive z) and has the following equation for the vertical displacement: w (2) = , ( - +) 48 The value of E is 200,000 Nmm²² and the values of ly is 20x 106 mm“ The maximum value of z for the beam cross section is ±20 mm What is the maximum tensile stress in the beam at the point when x = 90 mm? Express your answer in Nmm2, as a number to 2 dp, without the units.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![A symmetrical beam of length 300 mm is loaded with a force of 414 N downwards
(positive z) and has the following equation for the vertical displacement:
w (2) = , ( - +)
48
The value of E is 200,000 Nmm²² and the values of ly is 20x 106 mm“
The maximum value of z for the beam cross section is ±20 mm
What is the maximum tensile stress in the beam at the point when x = 90 mm?
Express your answer in Nmm2, as a number to 2 dp, without the units.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F83bbefa2-41ba-4db8-a0b6-4738307878bd%2F70efc06b-e6ad-4ef1-93ed-79077496feb0%2Fzv5sfem.png&w=3840&q=75)
Transcribed Image Text:A symmetrical beam of length 300 mm is loaded with a force of 414 N downwards
(positive z) and has the following equation for the vertical displacement:
w (2) = , ( - +)
48
The value of E is 200,000 Nmm²² and the values of ly is 20x 106 mm“
The maximum value of z for the beam cross section is ±20 mm
What is the maximum tensile stress in the beam at the point when x = 90 mm?
Express your answer in Nmm2, as a number to 2 dp, without the units.
Expert Solution
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Step 1
Given:
Length, L = 300 mm
Force, F = 414 N
Modulus of Elasticity, E = 2 x 105 N/mm2
Moment of inertia, Iy = 20 x 106 mm4
Maximum distance of extreme fiber from neutral axis, z = ±20 mm
Also, the equation for vertical displacement is given as,
Step 2
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