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A survey organization sampled 64 households in a community and found that the mean number of TV sets per household was 3.38. The standard deviation is 1.2. Can you conclude that the mean number of TV sets per household is greater than 3? Use the a = 0.01 level. a. State the null and alternative hypotheses. Ho: HV H₁: μV + + + + + + Critical value(s): 0.01 OF b. Find the critical value and sketch the rejection region. Sketch of Rejection Region: AAA + + + + -3 -2 -1 0 1 2 3 -3 -2 -1 0 1 2 3 -3 -2 -1 X 2.387 c. Find the test statistic. d. Find the p-value. 0.0070 = V X OT 3 OF 3 OF (If there are two critical values, list both values separated by a comma) + + + + 0 + 1 + 2 + 3 8

A survey organization sampled 64 households in a community and found that the mean number of TV sets per household was 3.38. The standard deviation is 1.2. Can you conclude that the mean number of TV sets per household is greater than 3? Use the a = 0.01 level. a. State the null and alternative hypotheses. Ho: HV H₁: μV + + + + + + Critical value(s): 0.01 OF b. Find the critical value and sketch the rejection region. Sketch of Rejection Region: AAA + + + + -3 -2 -1 0 1 2 3 -3 -2 -1 0 1 2 3 -3 -2 -1 X 2.387 c. Find the test statistic. d. Find the p-value. 0.0070 = V X OT 3 OF 3 OF (If there are two critical values, list both values separated by a comma) + + + + 0 + 1 + 2 + 3 8

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section: Chapter Questions
Problem 22SGR
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A survey organization sampled 64 households in a community and found that the mean number of TV sets per household was 3.38. The standard deviation is 1.2. Can you conclude that the mean number of TV sets per household is greater than 3? Use the a = 0.01 level. a. State the null and alternative hypotheses. ^d | : °H H1 : p v b. Find the critical value and sketch the rejection region. Sketch of Rejection Region: Critical value(s): जान्न गरिन्छ जान्न + + + -3 -2 -1 1 -1 0 1 3 -3 -2 -1 1 0.01 c. Find the test statistic. 2.387 x (If there are two critical values, list both values separated by a comma) d. Find the p-value. 0.0070 3 3 X o ४
Transcribed Image Text:A survey organization sampled 64 households in a community and found that the mean number of TV sets per household was 3.38. The standard deviation is 1.2. Can you conclude that the mean number of TV sets per household is greater than 3? Use the a = 0.01 level. a. State the null and alternative hypotheses. ^d | : °H H1 : p v b. Find the critical value and sketch the rejection region. Sketch of Rejection Region: Critical value(s): जान्न गरिन्छ जान्न + + + -3 -2 -1 1 -1 0 1 3 -3 -2 -1 1 0.01 c. Find the test statistic. 2.387 x (If there are two critical values, list both values separated by a comma) d. Find the p-value. 0.0070 3 3 X o ४
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