**Analyzing a Data Set of Household Plastic Disposals**A data set lists weights (lb) of plastic discarded by households. The highest weight recorded is 5.56 lb. The mean of all the weights is \( \bar{x} = 2.099 \, \text{lb} \) and the standard deviation of the weights is \( s = 1.101 \, \text{lb} \).**Questions:****a.** What is the difference between the weight of 5.56 lb and the mean of the weights?**b.** How many standard deviations is that [the difference found in part (a)]?**c.** Convert the weight of 5.56 lb to a z score.**d.** If we consider weights that convert to z scores between –2 and 2 to be neither significantly low nor significantly high, is the weight of 5.56 lb significant?---**Solutions:****a.** The difference is __________ lb. *(Type an integer or a decimal. Do not round.)***b.** The difference is __________ standard deviations. *(Round to two decimal places as needed.)***c.** The z score is \( z = \) __________. *(Round to two decimal places as needed.)***d.** The highest weight is [ ] *(Dropdown options for selection)*---**Explanation:**To solve these questions, follow these steps:1. **Calculate the difference between the highest weight and the mean:** \[ \text{Difference} = 5.56 \, \text{lb} - 2.099 \, \text{lb} \] 2. **Determine how many standard deviations this difference represents:** \[ \text{Standard deviations} = \frac{\text{Difference}}{s} \]3. **Compute the z score for the weight of 5.56 lb:** \[ z = \frac{5.56 \, \text{lb} - 2.099 \, \text{lb}}{1.101 \, \text{lb}} \]4. **Evaluate the significance based on the z score:** - If the z score is between -2 and 2, the weight is not significantly different from the mean. - Otherwise, the weight is considered significant.

Given X=5.56 X-bar=2.099 S=1.101

Answered: A data set lists weights (lb) of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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