A survey of 1000 students concluded that 274students chose a professional baseball team, A, ashis or her favorite team. In 1991, the same surveywas conducted involving 760 students. It concludedthat 240 of them also chose team A as their favorite.Compute a 95% confidence interval for thedifference between the proportion of studentsfavoring team A between the two surveys. Is there asignificant difference?(upload the picture of solution and roundoffyour final answer into 5 decimal places)

The question is about a confidence int. for a difference between two popl. prop. Given : No. of…

Answered: A survey of 1000 students concluded…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A graduate student is interested in how viewing different types of scenes affects working memory. For his study, he selects a random sample of 36 adults. The subjects complete a series of working memory tests before and after walking in an urban setting. Before the walk, the mean score on the test of working memory was 9.1. After the walk, the mean score was 1.4 higher. The graduate student has no presupposed assumptions about how viewing different types of scenes affects working memory, so he formulates the null and alternative hypotheses as: H00 : μDD = 0 H11 : μDD ≠ 0 Assume that the data satisfy all of the required assumptions for a repeated-measures t test. The graduate student calculates the following statistics for his hypothesis test: Mean difference (MDD) 1.4 Estimated population standard deviation of the differences (s) 1.6 Estimated standard error of the mean differences (sMDMD) 0.2667 Degrees of freedom (df) 35 The t statistic 5.25 The critical values of t…
Ten engineering schools in a country were surveyed. The sample contained 225electrical engineers, 80 being women; 175 chemical engineers, 40 being women. Compute a 90% confidence interval for the difference between the proportions of women in these two fields of engineering. Is there a significant difference between the two proportions? Let p1 be the population proportion of electrical engineers that are women in the schools that were surveyed and let p2 be the population proportion of chemical engineers that are women in the schools that were surveyed. The 90% confidence interval is nothing<p1−p2<nothing. (Round to three decimal places as needed.)
In 2003, an organization surveyed 1,508 adult Americans and asked about a certain war, "Do you believe the United States made the right or wrong decision to use military force?" Of the 1,508 adult Americans surveyed, 1,086 stated the United States made the right decision. In 2008, the organization asked the same question of 1,508 adult Americans and found that 573 believed the United States made the right decision. Construct and interpret a 90% confidence interval for the difference between the two population proportions, p2003−p2008.
Suppose that in a random selection of 100 colored candies, 23% of them are blue. The candy company claims that the percentage of blue candies is equal to 26%. Use a 0.05 significance level to test that claim.
Suppose that in a random selection of 100 colored candies, 20% of them are blue. The candy company claims that the percentage of blue candies is equal to 29%. Use a 0.01 significance level to test that claim.
A Michigan study concerning preference for outdoor activities used a questionnaire with a six-point Likert-type response in which 1 designated "not important" and 6 designated "extremely important." A random sample of n1 = 41 adults were asked about fishing as an outdoor activity. The mean response was x1 = 4.9. Another random sample of n2 = 50 adults were asked about camping as an outdoor activity. For this group, the mean response was x2 = 5.7. From previous studies, it is known that ?1 = 1.6 and ?2 = 1.5. Does this indicate a difference (either way) regarding preference for camping versus preference for fishing as an outdoor activity? Use a 5% level of significance.Note: A Likert scale usually has to do with approval of or agreement with a statement in a questionnaire. For example, respondents are asked to indicate whether they "strongly agree," "agree," "disagree," or "strongly disagree" with the statement. (a) What is the level of significance? .05 State the null and alternate…
Suppose that, in a comparison of two holiday companies’ customers, of the 75 who went with Happy Days Tours, 45 said they were satisfied, while 48 of the 90 who went with Fly by Night Holidays were satisfied. Test at a 2.5% significance level whether there is a difference in the true proportion of satisfied customers for the two companies?
A large manufacturing company claims that less than 10% of its customers make a complaint about the company’s products. Test this claim at the 10% significance level, if a survey found that 29 out of a random sample of 320 of the company’s customers made a complaint about the company’s products.
A lawyer researched the average number of years served by 45 different justices on the Supreme Court. The average number of years served was 13.8 years with a standard deviation of 7.3 years. What is the 95% confidence interval for the average number of years served by all Supreme Court justices? Question 6 options: 1) (11.7,15.9) 2) (11.8,15.8) 3) (12.9,16.9) 4) (12.5,17.3)
Suppose that in a random selection of 100 colored candies, 20% of them are blue. The candy company claims that the percentage of blue candies is equal to 22%. Use a 0.01 significance level to test that claim.
The dataset "nurses" is a random sample of 1,000 cases from “Health Care Provider Credential Data” from Washington State Open Data Portal. In the sample, there are 418 CNA's and 278 of the CNA's have expired credentials. Use the statistics from the nurses dataset to answer the following question: "With 90% confidence, what percent of all CNA's on Washington State's healthcare provider list are expired?"
A national research group reported that 36% of 18-24 year olds watch a cable news channel regularly. The director of media relations at a large university wanted to know what proportion of students at her university who watch a cable news channel regularly. If it is less than 36%, then she will unsubscribe to the news channels. She sampled 200 random students and found that 63 watched cable news regularly. Should she conclude that proportion of students at her university who watch cable news regularly is less than 36% at the 8% significance level? In the context of this problem and your conclusion, what type of error is possible? In the context of this problem, what would the error be? In the context of this problem, what would be a possible consequence of this error?

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