A survey of 1000 air travelers¹ found that 60 % prefer a window seat. The sample size is large enough to use the normal distribution,and a bootstrap distribution shows that the standard error is SE = 0.015.Use a normal distribution to find a 99% confidence interval for the proportion of air travelers who prefer a window seat.Round your answers to three decimal places.The 99% confidence interval is i 0.621to0.698

The sample size is 1000, the sample proportion is 0.60 and standard error is 0.015.

Answered: A survey of 1000 air travelers¹ found…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The distribution of study times for first-year students follow a Normal distribution with a standard deviation σ = 48 minutes. Suppose a sample of 344 students found that the mean study time for these students was x¯= 170 minutes per week. Use this to find a 94.38% confidence interval to estimate the mean study time for all students. We are 94.38% confident that the mean study time for first-year students is between the following ( answer) minutes and ( answer) minutes. The answer needs to be the mean study time for first-year students is between what amount of minutes and the following minutes.
If n = 550 and X = 440, construct a 90% confidence interval for the population proportion, p. Give your answers to three decimals < p <
In a survey, each participant indicated how much they agreed with the statement, "Hard work is the way to get what you want in life." Which of the following would you expect to have zero correlation, or close to zero correlation, with the response to the above statement? A) Agreement with the statement, "Happiness mostly depends on luck." B) Conscientiousness score on a personality inventory test. C) High school GPA. D) A random number between 0 and 10, chosen by the participant.
Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 17. (Round your answer to three decimal places.)
A professor was curious about her students' grade point averages. She took a random sample of 15 students and found a mean GPA of 3.01 with a standard deviation of 0.534. Which of the following formulas gives a 99% confidence interval for the mean GPA of the professor's students?
The National Longitudinal Study of Adolescent Health interviewed several thousand teens (grades 7 to 12). One question asked was “What do you think are the chances you will be married in the next 10 years?” Here is a two-way table of the responses by gender: Opinion Female Male Almost no chance 120 94 Some chance but probably not 156 178 A 50-50 chance 427 498 A good chance 750 700 Almost certain 1176 770 How many individuals are described in this table? How many females were among the respondents? The percent of females among the respondents was about %. Your percent from the previous exercise is part of the marginal distribution of opinion about marriage. the conditional distribution of sex among adolescents with a given opinion. the marginal distribution of sex. What percent of females thought that they were almost certain to be married in the next 10 years?% Your percent from the previous exercise is part of the conditional distribution of sex among…
Use the Student's t distribution to find tc for a 0.90 confidence level when the sample is 25. (Round your answer to three decimal places.)
Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 29. (Round your answer to three decimal places.)
A statistics practitioner took a random sample of 48 observations from a population whose standard deviation is 32 and computed the sample mean to be 107. Note: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the parentheses and the comma between the confidence limits. A. Estimate the population mean with 95% confidence. Confidence Interval = B. Estimate the population mean with 90% confidence. Confidence Interval = C. Estimate the population mean with 99% confidence. Confidence lInterval =

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