A survey found that the average hotel room rates and standard deviations for the state ofMassachusetts and the state of Wisconsin. Assume that the data were obtained from twosamples were normally distributed. At a=0.05 level of significance, can it be concluded thatthere is a significant difference in the rates? Use the data table below. Report only the valuerequired from the question below make sure to express your final answers in 4 decimalplaces.Parameter Massachusetts WisconsinSamplesize41.0036.00sample348.39356.53meanpopulationstandarddeviation30.8434.91а. р-value:

Answered: A survey found that the average hotel…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Psychology students at a university completed the Dental Anxiety Scale questionnaire. Scores on the scale range from 0 (no anxiety) to 20 (extreme anxiety). The mean score was 11 and the standard deviation was 3.5. Assume that the distribution of all scores on the Dental Anxiety Scale is normal with u = 11 and o = 3.5. Complete parts a through c. Click here to view a table of areas under the standardized normal curve. a. Suppose you score a 18 on the Dental Anxiety Scale. Find the z-value for this score. z= 2 (Round to the nearest hundredth as needed.) b. Find the probability that someone scores between 10 and 15 on the Dental Anxiety Scale. P(10sxs 15) = (Round to four decimal places as needed.) c. Find the probability that someone scores above 17 on the Dental Anxiety Scale. P(x> 17) =| (Round to four decimal places as needed.)
Please help me with the questions on attached document. Thanks!
Please answer a and b
The blood pressure in millimeters was measured for a large sample of people. The average pressure is 140 mm, and the SD of the measurements is 20 mm. The histogram looks reasonably like a normal curv Use the normal curve to estimate the following percentages. Choose the answer that is closest to being correct. A 19.1% B 30.9% C 38.2% D 69.1% E 68.27% A The percentage of people with blood pressure between 130 and 150 mm. B The percentage of people with blood pressure between 140 and 150 mm. D The percentage of people with blood pressure over 150 mm.
The amount of caffeine in a sample of five-ounce servings of brewed coffee is shown in the histogram. Make a frequency distribution for the data. Then use the table to estimate the sample mean and the sample standard deviation of the data set. Click the icon to view the histogram. Complete the table. Round values to the nearest tenth as needed. Graph/chart f Midpoint x xf 70.5 Ay 30- 92.5 26 25- 114.5 136.5 20- 158.5 15- 12 Ef = Exf = 10- Find the mean of the data set. 5- X = (Round to the nearest tenth as needed.) 48.5 70.5 92.5 114.5 136.5 158.5 Complete the table. Round values to the nearest tenth as needed. Midpoint x (x-x)? (x-x)?f X-X 70.5 Print Done 92.5 114.5 136.5 158.5 (x-x)?r= ] of
please answer the question in the photo. Thank you
II. Refer to the problem below. Show complete solutions. Box and label your final answers. The systolic blood pressure (given in millimeters) of females has an approximately normal distribution. 95% of the female students in a school have a systolic blood pressure between 97 mm and 153 mm. 1. Determine the mean. 2. Determine the standard deviation
Page 2 of 5 B. Organizing and Working with Data. 1. Find the z-score for the weight of a 155-pound woman. The mean weight of woman age 20 or older is 170.6 pounds with a standard deviation of 5.4 pounds. Round your answer to two decimal places.
Refer to the data set in the accompanying table. Assume that the paired sample data is a simple random sample and the differences have a distribution that is approximately normal. Use a significance level of 0.05 to test for a difference between the weights of discarded paper (in pounds) and weights of discarded plastic (in pounds). E Click the icon to view the data. In this example, Hg is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the weight of discarded paper minus the weight of discarded plastic for a household. What are the null and alternative hypotheses for the hypothesis test? O A. Ho: Ha = 0 H,: Ha #0 O B. Ho: Ha #0 H1: Hd =0 O C. Ho: Ha #0 O D. Ho: Ha = 0 H1: Hd 0
Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1. Find the probability that a given score is between -2.05 and 3.87 and draw a sketch of the region. Sketch the region. Choose the correct graph below. OA. OB. OC. OD. -2.05 3.87 2.05 3.87 -2.05 3.87 -2.05 3.87 The probability is (Round to four decimal places as needed.)
Compare the population variance to the mean of the sample variances. Choose the correct answer below. A. The population variance is equal to the square root of the mean of the sample variances. B. The population variance is equal to the mean of the sample variances. C. The population variance is equal to the square of the mean of the sample variances.
Find the range, the standard deviation, and the variance for the given samples. Round non-integer results to the nearest tenth. 74, 47, 85, 50, 62, 93, 56, 57, 75 range standard deviation variance

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