A study was done on body temperatures of men and women. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normaily distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level to test the claim that men have a higher mean body temperature than women. What are the null and alternative hypotheses?
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Q: A study was done on body temperatures of men and women. The results are shown in the table. Assume…
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A: Given: n1=11n2=59s1=0.89s2=0.63x¯1=97.76x¯2=97.32σ=0.01
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- A study was done on proctored and nonproctored tests. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a significance level 0.01 for both parts. ___________________________________________________________________ Proctored Nonproctored μ μ1 μ2 n 34 32 x 74.86 83.25 s 10.51 18.27 _______________________________________________ a) Test the claim that students taking nonproctored tests get a higher mean score than those taking proctored…Listed below are systolic blood pressure measurements (mm Hg) taken from the right and left arms of the same woman. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Use a 0.10 significance level to test for a difference between the measurements from the two arms. What can be concluded? Right arm 142 132 127 137 130 D Left arm 174 172 184 137 147 O A. Ho: Hd =0 B. Ho: Ha 0 H1: Hd =0 %3D OC. Ho: Hd = 0 H1: Hd 0 Identify the test statistic. (Round to two decimal places as needed.) t= Identify the P-value. P-value = (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test?A study was done on body temperatures of men and women. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. a. Test the claim that the two samples are from populations with the same mean. What are the null and alternative hypotheses? What is the test statistic, t? What is the P-value? State the conclusion for the test. b. Construct a confidence interval suitable for testing the claim that the two samples are from populations with the same mean.
- Seven acute schizophrenics and 10 chronic schizophrenics have been measured on a clarity of thinking scale. The mean for the acute sample was 52, with s = 12, and the mean for the chronic sample was 44, with s = 11. Perform a pooled-variance t test with alpha = .05 (two-tailed), and state your statistical conclusion.A study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples are independent simple random H samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. a. Test the claim that the two samples are from populations with the same mean. What are the null and alternative hypotheses? OA. Ho: #₁ = 1₂ H₁: H₁ H₂ OC. Ho: H₁A study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.10 significance level for both parts. a. Test the claim that the two samples are from populations with the same mean. What are the null and alternative hypotheses? OA. Ho: H₁ H₂ H₁: Hq ZH₂ OC. Ho: H₁ H₂ H₁: Hy > H₂ The test statistic, t, is. (Round to two decimal places as needed.) (Round to three decimal places as needed.) The P-value is State the conclusion for the test. C... OB. Ho: H₁ H₂ H₁: Hy #H₂ OD. Ho: Hg #U2 H₁: HyThe mean ACT score for 43 male high school students is 21.1 and the standard deviation is 5.0. The mean ACT score for 56 female high school students is 20.9 and the standard deviation is 4.7. At the 1% significance level, can you reject the claim that male and female high school students have equal ACT score averages? Be sure to use the p-value to make your conclusion.A study was done on body temperatures of men and women. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. a. Use a 0.01 significance level to test the claim that men have a higher mean body temperature than women. What are the null and alternative hypotheses? A. Ho: M₁ = ₂ H₁: H₁ H₂ C. Ho: M₁ = H2 H₁: H₁ H₂ The test statistic, t, is (Round to two decimal places as needed.) B. Ho: H₁ H₂ H₁ H₁A study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. a. Test the claim that the two samples are from populations with the same mean. What are the null and alternative hypotheses? OA. Ho: H₁ H₂ H₁: H₁ H₂ OC. Ho: H₁ H¹/₂ H₁: H₁Does color enhance creativity? Test the indicated claim about the standard deviations or variances of two populations. Subjects are given a creativity exercise on a computer with either a red background or a blue background. The scores are shown in the table. At the 0.05 significance level, test the claim that those tested with red background have creativity scores with a standard deviation equal to the standard deviation for those tested with a blue background. Red Background Blue Background n1 = 39 n2 = 34 xˉx̄1 = 19.6 xˉx̄2 = 20.5 s1 = 0.72 s2 = 0.01 What are the correct hypotheses? (Select the correct symbols and use decimal values not percentages.)H0: Select an answer x̄₂ x̄₁ μ(red) p₂ p μ₁ μ₂ σ₁ s₁² σ(red) p₁ μ p̂₁ ? ≠ < > ≤ ≥ = Select an answer μ₁ μ₂ p₁ μ(blue) p σ₂ p₂ σ(blue) s₁² x̄₁ x̄₂ μ p̂₁ H1: Select an answer μ σ₁ x̄₁ μ(red) p̂₂ p₁ s₂² p₂ μ₂ μ₁ σ(red) x̄₂ p ? ≤ ≥ ≠ > = < Select an answer μ(blue) σ(blue) p μ μ₁ p₁ x̄₂ s₁² x̄₁ σ₂ p̂₁ p₂ μ₂…Please help me answer this question in full!What is the Test Statistic and P-Value?SEE MORE QUESTIONSRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th…StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C…StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. 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