A study in Sweden compared former elite soccer players with people of the same age who had playedsoccer but not at the elite level. Of the 500 former elite soccer players surveyed, 44 % had developedarthritis of the hip or knee by their mid-50s, compared with 42 % of the 500 recreational soccer players.Does it appear that elite soccer players are more likely to develop arthritis of the hip or knee thancomparable recreational soccer players? Test at a = 0.10. Round your answers to three decimal places,and round any interim calculations to four decimal places.Fill in the hypotheses below where p₁ denotes the proportion of elite soccer players who develop arthritisof the hip or knee and på denotes the proportion of recreational soccer players who develop arthritis of thehip or knee.Ho: P₁Ha: P₁This test is right-tailed.P₂✓✓✓✓ P.What is the test statistic?Part 2 of 4

Given p1 denotes the proportion of elite soccer players who develop arthritis of the hip of knee and…

Answered: A study in Sweden compared former elite…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A dietician read in a survey that 70.5% of adults in the U.S. do not eat breakfast at least 3 days a week. She believes that the proportion that skip breakfast 3 days a week is different than 0.705. To verify her claim, she selects a random sample of 71 adults and asks them how many days a week they skip breakfast.. 44 of them report that they skip breakfast at least 3 days a week. Test her claim at a = 0.10. The correct hypotheses would be: О Но:р 0.705 (claim) Но: р > 0.705 HA:p < 0.705 (claim) О Но: р — 0.705 HA:P + 0.705 (claim) Since the level of significance is 0.10 the critical value is 1.645 and -1.645 The test statistic is: (round to 3 places) The p-value is: (round to 3 places) The decision can be made to: O reject Ho O do not reject Ho The final conclusion is that: O There is enough evidence to reject the claim that the proportion that skip breakfast 3 days a week is different than 0.705. O There is not enough evidence to reject the claim that the proportion that skip…
Supposed that in the past, 10% of women in the Philippines have severe dysmenorrhea. Do we have enough reason to believe that the proportion of women having terrible cramps has decreased if, in a random barangay population of 1,256 women, 122 have severe enough cramping to interfere with their daily lives? Use a = 0.05
A Verizon researcher compared the number of text messages sent by a sample of teenage boys to the population mean for all Verizon users. She found no evidence to conclude that there was a difference. Unfortunately, her conclusion was in error. (a) What type of error did she make? (b) What conclusion should she have reached?
In a recent poll six hundred adults were asked a series of questions about the state ofthe economy and their children’s future. One question was, “do you expect your children to have a better life than you have had, a worse life, or a life about the same asyours?” The responses showed 242 better, 310 worse, and 48 about the same. Use thesign test and a =.05 to determine whether there is a difference between the number ofadults who feel their children will have a better life compared to a worse life. What isyour conclusion?
It is bleieved that the percent of convicted felons who have a history of juvenile deliquency is 70%. Is there evidence to support the claim that the actual percentage is more than 70% if out of 200 convicted felons, we find that 154 have a history of juvenile deliquency? Set the level of significance at a = 0.05
A researcher wants to find the effect of a special diet on systolic blood pressure. A sample of 7 adults was selected to start them on this diet for 3 months. Based on this information, can it be stated that systolic blood pressure changes with the special diet? The test statistic that will determine whether systolic blood pressure changes with the special diet is...... A. 1.23 B. 0.48 C. 18.1 D. 21.08 E. 4.08
An article published in the Washington Post claims that 45 percent of all Americans have brown eyes. A random sample of ?=78n=78 college students students found 30 who had brown eyes.Consider testing ?0:?=.45H0:p=.45??:?≠.45 (b) P-value = ?
Support for the U.S. death penalty for convicted murderers was 63% in 2014 (Gallup poll results 2018). In a recent survey of 150 randomly selected U.S. adults, 75 said they were in favor of the death penalty for those convicted of murder. Does this sample appear to come from a population with a lower proportion in favor of the death penalty? d) Say that a = 0.05, what does this mean. Explain in the context of the problem. e) What would it mean to make a type II error? Explain in the context of this problem. f) Use a 0.05 significance level to test the claim. State your conclusion AND interpret your results.
On average, a sample of n = 36 scores will provide a better estimate of the population mean than a sample of n = 49 scores from the same population.
You read a newspaper article that says that 74% of households in your town participate in a recycling program. To test that statement at the 10% significance level, you randomly select 54 households in town and you find that 35 of them participate in the recycling program. Ho: P=0.74 Ha:P=/ 0.74 Find the P-value. Round your answer to 3 decimal places.
Can you find and show the p-value for this question?
In a data set with 25 scores, if the value 16 occurs 12 times, what is its relative frequency?

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