A student was asked to find a 95% confidence interval for widget width using data from a random sample ofsize n = 29. Which of the following is a correct interpretation of the interval 12.5 < μ< 35?Check the box that corresponds to the correct interpretation.There is a 95% chance that the mean of a sample of 29 widgets will be between 12.5 and 35.With 95% confidence, the mean width of a randomly selected widget will be between 12.5 and 35.With 95% confidence, the mean width of all widgets is between 12.5 and 35.The mean width of all widgets is between 12.5 and 35, 95% of the time. We know this is true becausethe mean of our sample is between 12.5 and 35.There is a 95% chance that the mean of the population is between 12.5 and 35.

Given that Sample size n =29 95% confidence interval 12.5< μ <35

Answered: A student was asked to find a 95%…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A quality control expert at a drink bottling factory took a random sample of 9 bottles from a production run of over 1,000 bottles and measured the amount of liquid in each bottle in the sample. The sample data were roughly symmetric with a mean of 505 mL and a standard deviation of 6 mL. Based on this sample, which of the following is a 95% confidence interval for the mean amount of liquid per bottle (in mL) in this production run? Choose 1 answer: A 505 3.720 505 3.920 505 +4.524 D505 +4.612 E505 + 12
What is the answer?
For a sample 1000 website users, the research department reports an average age of 39. If the population standard deviation is 9.5 years, what would be the upper bound for a 90% confidence interval estimate of the mean age of all users?
Contstruct a 95% confidence interval for the population mean length of time that people have lived in the city, town, or community where they live now.
#2 A sample of 64 airplanes gave a mean air time (time spent flying) of 49 hours. If the standard deviation is 14.8 hours, construct a 90% confidence interval for u, the true mean air time.
a simple random sample of 9 college freshmen were asked how many hour of sleep they typically got per night. The results were 8.5,6.5,8,9,6,7.5,24,8.5,9.5. Elminate the outlier, then consturct a 90% confidence interval for the mean amount of sleep from the remaining values.
A researcher reports t(5) = +3.00, p < .05 for a repeated-measures research study. The mean sample difference score for the sample was MD = 12. Which of the following is the confidence interval for the population mean difference?
A sample of 20 bags of mulch had a mean weight of 52 pounds with a standard deviation of 3.8 pounds. Find the 95% confidence interval of the true mean. Show all your work for or explain how you obtained your answer in the space provided below.
A student was asked to find a 98% confidence interval for widget width using data from a random sample of size n = 22. Which of the following is a correct interpretation of the interval 13.7 < μ < 27.5? Check all that are correct. The mean width of all widgets is between 13.7 and 27.5, 98% of the time. We know this is true because the mean of our sample is between 13.7 and 27.5. There is a 98% chance that the mean of a sample of 22 widgets will be between 13.7 and 27.5. There is a 98% chance that the mean of the population is between 13.7 and 27.5. With 98% confidence, the mean width of a randomly selected widget will be between 13.7 and 27.5. With 98% confidence, the mean width of all widgets is between 13.7 and 27.5.
A student was asked to find a 90% confidence interval for widget width using data from a random sample of size n = 20. Which of the following is a correct interpretation of the interval (11.5,21.6)? There is a 90% chance that the mean of a sample of 20 widgets will be between 11.5 and 21.6. The mean width of all widgets is between 11.5 and 21.6, 90% of the time. We know this is true because the mean of our sample is between 11.5 and 21.6. With 90% confidence, the mean width of a randomly selected widget will be between 11.5 and 21.6. We are 90% confident the mean width of all widgets is between 11.5 and 21.6. There is a 90% chance that the mean of the population is between 11.5 and 21.6.
A student was asked to find a 98% confidence interval for widget width using data from a random sample of size n = 26. Which of the following is a correct interpretation of the interval 13.5 < μ < 29.3? Check all that are correct. The mean width of all widgets is between 13.5 and 29.3, 98% of the time. We know this is true because the mean of our sample is between 13.5 and 29.3. With 98% confidence, the mean width of a randomly selected widget will be between 13.5 and 29.3. There is a 98% chance that the mean of a sample of 26 widgets will be between 13.5 and 29.3. There is a 98% chance that the mean of the population is between 13.5 and 29.3. With 98% confidence, the mean width of all widgets is between 13.5 and 29.3.
Suppose a randomly selected sample of n = 69 men has a mean foot length of x = 27.9 cm, and the standard deviation of the sample is 3 cm. Calculate an approximate 95% confidence interval for the mean foot length of men. (Round the answers to one decimal place.)

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