A student was asked to find a 98% confidence interval for widget width using data from a random sample ofsize n = 26. Which of the following is a correct interpretation of the interval 14.3 < µ< 28.9?There is a 98% chance that the mean of a sample of 26 widgets will be between 14.3 and 28.9.With 98% confidence, the mean width of all widgets is between 14.3 and 28.9.There is a 98% chance that the width of the widget is between 14.3 and 28.9.The width of all widgets is between 14.3 and 28.9, 98% of the time. We know this is true because themean of our sample is between 14.3 and 28.9.With 98% confidence, the width of a randomly selected widget will be between 14.3 and 28.9.

Given 98% confidence interval for population mean μ is (14.3,28.9)

Answered: A student was asked to find a 98%…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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2) (9.2) Suppose a random sample of 1001 Americans age 15 or older were asked "How much time do you spend eating or drinking per day?" Of the 1001 participants, the mean amount of time spent eating or drinking per day is 1.22 hours with a standard deviation of 0.65 hours. Determine a 99% confidence interval for the mean amount of time Americans age 15 or older spend eating or drinking each day.
The researcher took a random sample of 50 residents and found that the mean height of men is 175cm. Suppose that the team is made aware of the fact that the distribution of heights is distributed normally. 1, The sample median is an unbiased estimate of the mean height of men. Is the following statement about the estimator true? 2, Determine whether or not the median or mean is an efficient estimator of the population median.
a simple random sample of 9 college freshmen were asked how many hour of sleep they typically got per night. The results were 8.5,6.5,8,9,6,7.5,24,8.5,9.5. Elminate the outlier, then consturct a 90% confidence interval for the mean amount of sleep from the remaining values.
A random sample of 49 Europeans was asked how many days of vacation they take each year. The sample mean was 30 and the population standard deviation is known to be 4. What is the 99% confidence interval of the true population parameter describing average vacation days?
A student was asked to find a 98% confidence interval for widget width using data from a random sample of size n = 22. Which of the following is a correct interpretation of the interval 13.7 < μ < 27.5? Check all that are correct. The mean width of all widgets is between 13.7 and 27.5, 98% of the time. We know this is true because the mean of our sample is between 13.7 and 27.5. There is a 98% chance that the mean of a sample of 22 widgets will be between 13.7 and 27.5. There is a 98% chance that the mean of the population is between 13.7 and 27.5. With 98% confidence, the mean width of a randomly selected widget will be between 13.7 and 27.5. With 98% confidence, the mean width of all widgets is between 13.7 and 27.5.
Suppose an electrical firm manufactures light bulbs that have a length of life that isnormally distributed, with a standard deviation of 55 hours. If a random sample of 27 bulbs has a mean length of life of 1,320 hours, find a 99% confidence interval for the population mean length of life of all bulbs produced by this firm. Interpret this interval.
A student was asked to find a 99% confidence interval for widget width using data from a random sample of size n = 24. Which of the following is a correct interpretation of the interval 12 to 33.6? The mean width of all widgets is between 12 and 33.6, 99% of the time. We know this is true because the mean of our sample is between 12 and 33.6. We are 99% confident that the mean width of a randomly selected widget will be between 12 and 33.6. There is a 99% chance that the mean of a sample of 24 widgets will be between 12 and 33.6. We are 99% confident that the mean width of all widgets is between 12 and 33.6. Which is true?
A student was asked to find a 90% confidence interval for widget width using data from a random sample of size n = 20. Which of the following is a correct interpretation of the interval (11.5,21.6)? There is a 90% chance that the mean of a sample of 20 widgets will be between 11.5 and 21.6. The mean width of all widgets is between 11.5 and 21.6, 90% of the time. We know this is true because the mean of our sample is between 11.5 and 21.6. With 90% confidence, the mean width of a randomly selected widget will be between 11.5 and 21.6. We are 90% confident the mean width of all widgets is between 11.5 and 21.6. There is a 90% chance that the mean of the population is between 11.5 and 21.6.
A student was asked to find a 98% confidence interval for widget width using data from a random sample of size n = 26. Which of the following is a correct interpretation of the interval 13.5 < μ < 29.3? Check all that are correct. The mean width of all widgets is between 13.5 and 29.3, 98% of the time. We know this is true because the mean of our sample is between 13.5 and 29.3. With 98% confidence, the mean width of a randomly selected widget will be between 13.5 and 29.3. There is a 98% chance that the mean of a sample of 26 widgets will be between 13.5 and 29.3. There is a 98% chance that the mean of the population is between 13.5 and 29.3. With 98% confidence, the mean width of all widgets is between 13.5 and 29.3.
A music manager wanted to construct a 95% confidence interval for the lenght of songs produced at his recording studio. Using data from a random sample of 47 songs, he obtained an interval of 3.05 < μ < 4.45. Which of the following is the correct interpretation of the interval? With 95% confidence, the mean width of all widgets is between 3.05 and 4.45. The mean width of all widgets is between 3.05 and 4.45, 95% of the time. We know this is true because the mean of our sample is between 3.05 and 4.45. There is a 95% chance that the mean of the population is between 3.05 and 4.45. With 95% confidence, the mean width of a randomly selected widget will be between 3.05 and 4.45. There is a 95% chance that the mean of a sample of 47 widgets will be between 3.05 and 4.45.
10
A 95% confidence interval for the mean was computed with a sample of size 90 to be (16,22). b. What is the point estimate x̅ ?

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