A student was asked how manygrams of H,O would be producedfrom 12.85 g of CaCN,. They wereprovided with the balanced equationand reaction map shown. Explain whytheir solution below is incorrect andwhere their mistake(s) is. Thencorrect the error and solve.CACN2 (s) + 3 H2O (1) → 2 NH3 (g) + CaCO3 (s)Grams ofGramsMillilitersGrams ofCACN2of H2Oof NH3СаСО3 mol H2O2 mol NH31 mol CaCO3Moles ofMoles ofMoles ofMoles of1 mol CACN23 mol H;02 mol NH3CACN2 (s)H2O (I)NH3 (g)CACO3 (s)Here is the student's solution:1 mol CaCN21 mol H2012.85 g CaCN2 X= 0.0077 g H2092.11 g CaCN218.02 g H201 mol CACO;100.09 g CaCO30.000045 mol NH3I milliliter1 mol H2O18.02 g H2O1 mol CACN292.11 g CaCN2

The balanced reaction taking place is given as, => CaCN2 (s) + 3 H2O (l) -----> 2 NH3 (g) +…

A student was asked how many grams of H,O would be produced from 12.85 g of CaCN,. They were provided with the balanced equation and reaction map shown. Explain why their solution below is incorrect and where their mistake(s) is. Then correct the error and solve. CACN2 (s) + 3 H,O (I) → 2 NH3 (g) + CaCO; (s) Grams of Grams Milliliters Grams of CACN2 of H2O of NH3 CaCO3 3 mol H2O 2 mol NH3 1 mol CACO; Moles of Moles of Moles of Moles of 1 mol CaCN2 3 mol H;O 2 mol NH3 CACN2 (s) H;O (I) NH3 (g) CACO, (s) Here is the student's solution: 1 mol CaCN2 92.11 g CaCN, ^ 18.02 g H20 1 mol H20 12.85 g CaCN2 x; 0.0077 g H20 I mol CaCO; 100.09 g CACO; 0.000045 mol NH3 I milliliter I mol H2O 18.02 g H;0 I mol CaCN2 92.11 g CACN2

A student was asked how many grams of H,O would be produced from 12.85 g of CaCN,. They were provided with the balanced equation and reaction map shown. Explain why their solution below is incorrect and where their mistake(s) is. Then correct the error and solve. CACN2 (s) + 3 H,O (I) → 2 NH3 (g) + CaCO; (s) Grams of Grams Milliliters Grams of CACN2 of H2O of NH3 CaCO3 3 mol H2O 2 mol NH3 1 mol CACO; Moles of Moles of Moles of Moles of 1 mol CaCN2 3 mol H;O 2 mol NH3 CACN2 (s) H;O (I) NH3 (g) CACO, (s) Here is the student's solution: 1 mol CaCN2 92.11 g CaCN, ^ 18.02 g H20 1 mol H20 12.85 g CaCN2 x; 0.0077 g H20 I mol CaCO; 100.09 g CACO; 0.000045 mol NH3 I milliliter I mol H2O 18.02 g H;0 I mol CaCN2 92.11 g CACN2

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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