When 0.629 g of Na3PO4 (molar mass = 163.94 g/mol) and 0.527 g of BaCl2 (molar mass = 208.23 g/mol) are mixed together in 500. mL of water, barium phosphate, Ba3(PO4)2 (molar mass = 601.96 g/mol), precipitates out. Assume 100% yield for the reaction. Determine how many grams of each product and each reactant are left at the end of the reaction. Units are not required as part of your answer for any of the following questions; just enter the numerical value with the correct significant figures.

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When 0.629 g of Na3PO4 (molar mass = 163.94 g/mol) and 0.527 g of BaCl2 (molar
mass = 208.23 g/mol) are mixed together in 500. mL of water, barium phosphate,
Ba3(PO4)2 (molar mass = 601.96 g/mol), precipitates out. Assume 100% yield for the
reaction.
Determine how many grams of each product and each reactant are left at the end of
the reaction. Units are not required as part of your answer for any of the following
questions; just enter the numerical value with the correct significant figures.
Transcribed Image Text:When 0.629 g of Na3PO4 (molar mass = 163.94 g/mol) and 0.527 g of BaCl2 (molar mass = 208.23 g/mol) are mixed together in 500. mL of water, barium phosphate, Ba3(PO4)2 (molar mass = 601.96 g/mol), precipitates out. Assume 100% yield for the reaction. Determine how many grams of each product and each reactant are left at the end of the reaction. Units are not required as part of your answer for any of the following questions; just enter the numerical value with the correct significant figures.
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