A student ran the following reaction in the laboratory at 526 K: COCl2(g) CO(g) + Cl2(g) When she introduced 1.77 moles of COCl2(g) into a 1.00 liter container, she found the equilibrium concentration of Cl2(g) to be 3.47×10-2 M. Calculate the equilibrium constant, Kc, she obtained for this reaction.

Q: A student ran the following reaction in the laboratory at 1098 K: 2SO3(g) 2SO2(g) + O2(g) When she…

A: Initial concentration of SO3= 8.35×10-2 moles ÷ 1L = 8.35×10-2 M.

Q: A student ran the following reaction in the laboratory at 703 K:      H2(g) + I2 (g) = 2HI (g) When…

A: The objective of the question is to calculate the equilibrium constant, Kc, for the reaction H2(g) +…

Q: Calculate the equilibrium constant, Kc,

A: The equilibrium constant, Kc, is the ratio of the equilibrium concentrations of products over the…

Q: A student ran the following reaction in the laboratory at 617 K: Co(g) + Cl2(g) = cocl2(g) When she…

A:

Q: A student ran the following reaction in the laboratory at 271 K: 2NO(g) + Br2(g) = 2NOBR(g) When she…

A:

Q: The reaction CO (g)  +  H2O (g)  ↔   CO2 (g)  +  H2 (g) is used to increase the ratio of hydrogen…

A: ICE table for the reaction is shown below.

Q: Tabo PC13 (g) + Cl₂ (g) ⇒ PC15 (9) she introduced 0.0811 moles of PC13 (9) and d the equilibrium…

A:

Q: 3 A(g) + B(g) = 2C(g) + 2 D(g)

A: Equilibrium constant is defined as the ratio of product of concentration of products to that of…

Q: A student ran the following reaction in the laboratory at 731 K: H2(g) + I2(g) = 2HI(g) When she…

A: Kc is the reaction quotient at equilibrium

Q: When she introduced 1.60 moles of COCl2(g) into a 1.00 liter container, she found the equilibrium…

A: Molarity of COCl2 = moles / Volume of solution Volume of container = volume of solution =1 L Moles…

Q: A student ran the following reaction in the laboratory at 567 K: CO(g) + Cl2(g) COCl2(g) When she…

A: Given data: Initial moles of CO (g) = 0.540 moles, Initial moles of Cl2 (g) = 0.551 moles, Volume =…

Q: A student ran the following reaction in the laboratory at 529 K: COC12 (9)CO(g) + Cl₂ (9) When she…

A: The equilibrium constant of a reaction is defined as the ratio of the concentration of products to…

Q: A student ran the following reaction in the laboratory at 531 K: PC13 (g) + Cl₂ (9) ⇒ PC15 (9) When…

A: Using the concentration terms at equilibrium, the equilibrium constant, Kc can be calculated.

Q: A student ran the following reaction in the laboratory at 635 K: 2 HI (g)  H2 (g) + I2 (g) When…

A: Moles of HI introduced = 0.404 Volume of container = 1.00L Concentration of HI =…

Q: A student ran the following reaction in the laboratory at 290 K: 2CH2CI2(g) =CH4(g) + CCI4(g) When…

A:

Q: A student ran the following reaction in the laboratory at 547 K: COCl2 = CO+ Cl2 When she introduced…

A: The objective of the question is to calculate the equilibrium constant, Kc, for the reaction COCl2 =…

Q: The compound NOCl decomposes to nitric oxide and chlorine according to the following equation: 2…

A: Given, 2 NOCl (g) → 2 NO (g) + Cl2 (g) Initially moles of NOCl = 0.510 mol Volume of the flask =…

Q: A student ran the following reaction in the laboratory at 540 K: COCI₂(g) →CO(g) + Cl₂(g) When she…

A: Answer:For any reaction, value of equilibrium constant is equal to the ratio of molar concentration…

Q: student ran the following reaction in the laboratory at 292 K: 2CH2Cl2(g) CH4(g) + CCl4(g) When…

A: The question is based on the principle equilibrium. we have been given equilibrium concentration of…

Q: A student ran the following reaction in the laboratory at 526 K: COC1₂ (g) CO(g) + Cl₂ (g) When she…

A:

Q: A student ran the following reaction in the laboratory at 540 K: COC12 (g) CO(g) + Cl₂ (g) When she…

A: Reaction COCl2(g) -------->CO(g) + Cl2(g)

Q: The decomposition of dinitrogen pentoxide, N2O5 is shown as follow: 2N2O5 (g) = 4NO2 (g) + O2 (g)…

A: The equilibrium constant is equal to the ratio of the concentration of product and concentration of…

Q: A student ran the following reaction in the laboratory at 431 K: PCI5 (g) PCI3 (g) + Cl2 (g) When…

A: Given : Moles of PCl5 = 2.91 moles

Q: A student ran the following reaction in the laboratory at 534 K: CoCI2 (g) co (g) + Cl2 (g) When she…

A:

Q: A student ran the following reaction in the laboratory at 565 K: Co(g) + Cl2(g) = cocl2(g) When she…

A: Recall the given reaction :     CO (g) +  Cl2 (g)  <------>  COCl2 (g)  The equilibrium…

Q: A student ran the following reaction in the laboratory at 682 K: H₂(g) + 12 (9) 2HI(g) When she…

A: The relation between the concentrations of products and reactants is related by a term known as…

Q: A student ran the following reaction in the laboratory at 545 K: COC12 (g) CO(g) + Cl₂ (g) When she…

A:

Q: A student ran the following reaction in the laboratory at 538 K: COCl2(g) CO(g) + Cl2(g) When she…

A:

Q: A student ran the following reaction in the laboratory at 290 K: 2CH2Cl2(g) CH4(g) + CCl4(g) When…

A: The chemical equation :  2CH2Cl2(g)  ----> CH4(g) + CCl4(g)  Number of moles of CH2Cl2 = 8.37…

Q: Given the following chemical system: 4NH3(s) + 502(g) → 4NO(g) + 6H2O(g) If 0.35 mol of both…

A: The equilibrium concentration with equilibrium constant can be calculated as :-

Q: A student ran the following reaction in the laboratory at 286 K: 2CH2Cl2(g) CH4(g) + CCl4(g) When…

A: 2CH2Cl2(g)     =     CH4(g)       +   CCl4(g) Kc = [CH4][CCl4]/[CH2Cl2]2

Q: A student ran the following reaction in the laboratory at 672 K: 2NH3(g)     N2(g) + 3H2(g) When…

A:

Q: A student ran the following reaction in the laboratory at 431 K: PCI 5(9) PC13(g) + Cl₂(9) When she…

A: Given, the equilibrium reaction as follows, PCl5(g) ⇌ PCl5(g)+Cl2 (g) with initial amount of PCl5…

Q: A student ran the following reaction in the laboratory at 70 K: H2(g) + I2(g) 2HI(g) When she…

A:

Q: A student ran the following reaction in the laboratory at 282 K: 2CH,Cl½(g) CH4(g) + CC14(g) When…

A: Given data,Initial moles of CH2Cl2=6.98×10-2molVolume of container=1.0LEquilibrium concentration of…