A student ran the following reaction in the laboratory at 375 K: CH4(g) + CCI4(g) = 2CH2CI2(g) When she introduced 4.58x10-2 moles of CH4(g) and 6.00x102 moles of CCI4(g) into a 1.00 liter container, she found the equilibrium concentration of CH2CI2(g) to be 1.68x10-2 M. Calculate the equilibrium constant, Kc, she obtained for this reaction.
A student ran the following reaction in the laboratory at 375 K: CH4(g) + CCI4(g) = 2CH2CI2(g) When she introduced 4.58x10-2 moles of CH4(g) and 6.00x102 moles of CCI4(g) into a 1.00 liter container, she found the equilibrium concentration of CH2CI2(g) to be 1.68x10-2 M. Calculate the equilibrium constant, Kc, she obtained for this reaction.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![A student ran the following reaction in the laboratory at 375 K:
CH4(g) + CC14(g) = 2CH2C22(g)
When she introduced 4.58x10 2 moles of CH4(g) and 6.00x102 moles of CCI4(g) into a 1.00 liter container, she found the equilibrium concentration of CH2CI2(g) to be
1.68x10-2 M.
Calculate the equilibrium constant, K, she obtained for this reaction.
K. =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1fab06c7-b3ec-41a6-becb-f832628650ea%2Fbd9192fc-4711-404f-acc7-bdd21001479a%2Ftzn9hc8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A student ran the following reaction in the laboratory at 375 K:
CH4(g) + CC14(g) = 2CH2C22(g)
When she introduced 4.58x10 2 moles of CH4(g) and 6.00x102 moles of CCI4(g) into a 1.00 liter container, she found the equilibrium concentration of CH2CI2(g) to be
1.68x10-2 M.
Calculate the equilibrium constant, K, she obtained for this reaction.
K. =
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