A student ran the following reaction in the laboratory at 742 K: N2(g) + 3H2(g) 2NH3(g) When she introduced 3.31×10-2 moles of N2(g) and 5.98×10-² moles of H2(g) into a 1.00 liter container, she found the equilibrium concentration of NH3(g) to be 8.31×10-4 M. Calculate the equilibrium constant, Ke, she obtained for this reaction.
A student ran the following reaction in the laboratory at 742 K: N2(g) + 3H2(g) 2NH3(g) When she introduced 3.31×10-2 moles of N2(g) and 5.98×10-² moles of H2(g) into a 1.00 liter container, she found the equilibrium concentration of NH3(g) to be 8.31×10-4 M. Calculate the equilibrium constant, Ke, she obtained for this reaction.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![A student ran the following reaction in the laboratory at 742 K:
N2(g) + 3H2(g)
2ΝH (g)
When she introduced 3.31x102 moles of N2(g) and 5.98x102 moles of H(g) into a 1.00 liter container, she found the equilibrium concentration of NH3(g) to be 8.31×104 M.
Calculate the equilibrium constant, K, she obtained for this reaction.
K. =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F95b89359-901f-4422-a865-0c53ae89839c%2F241cd167-d455-4023-9e75-f82b0d2e4d73%2F1xuufcx_processed.png&w=3840&q=75)
Transcribed Image Text:A student ran the following reaction in the laboratory at 742 K:
N2(g) + 3H2(g)
2ΝH (g)
When she introduced 3.31x102 moles of N2(g) and 5.98x102 moles of H(g) into a 1.00 liter container, she found the equilibrium concentration of NH3(g) to be 8.31×104 M.
Calculate the equilibrium constant, K, she obtained for this reaction.
K. =
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