A student performed an alkylation of 1,4-dicyanobenzene (1) using tert-butyl alcohol (2). N=C- What will his major product be? O 1,2,4,5-tetra-tert-butyl-3,6-dicyanobenzene There is no reaction; no product is formed O The correct product is not given -C=N O 1,4-di-tert-butyl-2,5-dicyanobenzene O 1-tert-butyl-2,5-dicyanobenzene H3C- CH3 CH3 -OH H₂SO4 ?
A student performed an alkylation of 1,4-dicyanobenzene (1) using tert-butyl alcohol (2). N=C- What will his major product be? O 1,2,4,5-tetra-tert-butyl-3,6-dicyanobenzene There is no reaction; no product is formed O The correct product is not given -C=N O 1,4-di-tert-butyl-2,5-dicyanobenzene O 1-tert-butyl-2,5-dicyanobenzene H3C- CH3 CH3 -OH H₂SO4 ?
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![A student performed an alkylation of 1,4-dicyanobenzene (1) using tert-butyl alcohol (2).
N=C
What will his major product be?
O
1,2,4,5-tetra-tert-butyl-3,6-dicyanobenzene
O There is no reaction; no product is formed
O The correct product is not given
O 1,4-di-tert-butyl-2,5-dicyanobenzene
C=N
O 1-tert-butyl-2,5-dicyanobenzene
CH3
H3C-C-OH H₂SO4
CH3
?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd19ff566-c8be-43f9-acfb-b5f0881fc005%2Fb37e67a7-e6cc-4f98-944f-8a5960af996d%2Fxnmavu_processed.png&w=3840&q=75)
Transcribed Image Text:A student performed an alkylation of 1,4-dicyanobenzene (1) using tert-butyl alcohol (2).
N=C
What will his major product be?
O
1,2,4,5-tetra-tert-butyl-3,6-dicyanobenzene
O There is no reaction; no product is formed
O The correct product is not given
O 1,4-di-tert-butyl-2,5-dicyanobenzene
C=N
O 1-tert-butyl-2,5-dicyanobenzene
CH3
H3C-C-OH H₂SO4
CH3
?
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