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(c) A 1.223-g sample of solid containing ascorbic acid and inert ingredients was dissolved in dilute H₂SO4 and treated with 2 g of KI and 50.00 mL of KIO, solution from part (a). Excess triiodide

(c) A 1.223-g sample of solid containing ascorbic acid and inert ingredients was dissolved in dilute H₂SO4 and treated with 2 g of KI and 50.00 mL of KIO, solution from part (a). Excess triiodide

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Solve 16.24 part C only

16-24. (a) Potassium iodate solution was prepared by dissolving 1.022 g of KIO3 (FM 214.00) in a 500-mL volumetric flask. Then 50.00 mL of the solution was pipetted into a flask and treated with excess KI (2 g) and acid (10 mL of 0.5 M H₂SO4). How many moles of I are created by the reaction? (b) The triiodide from part (a) reacted with 37.66 mL of Na₂S₂O3 solution. What is the concentration of the Na₂S₂O3 solution? (c) A 1.223-g sample of solid containing ascorbic acid and inert ingredients was dissolved in dilute H₂SO4 and treated with 2 g of KI and 50.00 mL of KIO3 solution from part (a). Excess triiodide
Transcribed Image Text:16-24. (a) Potassium iodate solution was prepared by dissolving 1.022 g of KIO3 (FM 214.00) in a 500-mL volumetric flask. Then 50.00 mL of the solution was pipetted into a flask and treated with excess KI (2 g) and acid (10 mL of 0.5 M H₂SO4). How many moles of I are created by the reaction? (b) The triiodide from part (a) reacted with 37.66 mL of Na₂S₂O3 solution. What is the concentration of the Na₂S₂O3 solution? (c) A 1.223-g sample of solid containing ascorbic acid and inert ingredients was dissolved in dilute H₂SO4 and treated with 2 g of KI and 50.00 mL of KIO3 solution from part (a). Excess triiodide
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