A student is diluting an aqueous NH4SCN solution for an experiment. The student starts with a 0.100 ± 0.003 M stock solution. The student pipettes 20.0 ± 0.2 mL of the stock solution into a 100.00 ± 0.08 mL volumetric flask, fills to the engraved line with deionized water, and then thoroughly mixes the solution to ensure homogeneity. What is the calculated diluted molarity of the NH4SCN solution in the volumetric flask with error? You will enter your answer in the following questions. What is the calculated absolute error on the diluted NH4SCN molarity?

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### Dilution of an Aqueous NH₄SCN Solution: Calculation and Error Determination

A student is diluting an aqueous NH₄SCN solution for an experiment. The student starts with a 0.100 ± 0.003 M stock solution. The student pipettes 20.0 ± 0.2 mL of the stock solution into a 100.00 ± 0.08 mL volumetric flask, fills to the engraved line with deionized water, and then thoroughly mixes the solution to ensure homogeneity.

**Question: What is the calculated diluted molarity of the NH₄SCN solution in the volumetric flask with error?**

You will enter your answer in the following questions.

---

**Question: What is the calculated absolute error on the diluted NH₄SCN molarity?**

*Input your answer in the provided textbox:*

[Textbox]

This scenario involves practical applications of molarity, dilution, and error propagation in a laboratory setting. Understanding how to determine the final molarity and the associated absolute error helps in developing important skills in precision and accuracy necessary for scientific experiments.

#### Detailed Calculation Process
1. **Initial Molarity (C₁)**: 0.100 ± 0.003 M
2. **Volume of Stock Solution (V₁)**: 20.0 ± 0.2 mL
3. **Final Volume (V₂)**: 100.00 ± 0.08 mL

From the dilution formula:
\[ C₁V₁ = C₂V₂ \]

Solving for the final concentration \( C₂ \) (diluted molarity):
\[ C₂ = \frac{C₁V₁}{V₂} \]

Understanding the absolute error will require conducting error propagation calculations using the given uncertainties for the concentration and volumes.
Transcribed Image Text:### Dilution of an Aqueous NH₄SCN Solution: Calculation and Error Determination A student is diluting an aqueous NH₄SCN solution for an experiment. The student starts with a 0.100 ± 0.003 M stock solution. The student pipettes 20.0 ± 0.2 mL of the stock solution into a 100.00 ± 0.08 mL volumetric flask, fills to the engraved line with deionized water, and then thoroughly mixes the solution to ensure homogeneity. **Question: What is the calculated diluted molarity of the NH₄SCN solution in the volumetric flask with error?** You will enter your answer in the following questions. --- **Question: What is the calculated absolute error on the diluted NH₄SCN molarity?** *Input your answer in the provided textbox:* [Textbox] This scenario involves practical applications of molarity, dilution, and error propagation in a laboratory setting. Understanding how to determine the final molarity and the associated absolute error helps in developing important skills in precision and accuracy necessary for scientific experiments. #### Detailed Calculation Process 1. **Initial Molarity (C₁)**: 0.100 ± 0.003 M 2. **Volume of Stock Solution (V₁)**: 20.0 ± 0.2 mL 3. **Final Volume (V₂)**: 100.00 ± 0.08 mL From the dilution formula: \[ C₁V₁ = C₂V₂ \] Solving for the final concentration \( C₂ \) (diluted molarity): \[ C₂ = \frac{C₁V₁}{V₂} \] Understanding the absolute error will require conducting error propagation calculations using the given uncertainties for the concentration and volumes.
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